CODEWITHSUNDEEP
javascriptmethod-call
Adag89
Adag89

Reputation: 161

I'm confused about call(), why doesn't my code work?

I'd like to call a function from Mammal, to use with Cat. I thought I understood it, but every time I try to use it, I get really confused.

function Mammal(legs,sound, commonName) {
    this.legs = legs;
    this.sound = sound;
    this.commonName = commonName;
    this.talk = function() {
        console.log(this.sound);
    }
}

const wolf = new Mammal(4, 'GRRRRRR', 'Wolf');

const dog = new Mammal(4, 'WOOF', 'Dog');

console.log(wolf)
console.log(dog.talk())

const cat = function(legs, sound, commonName) {
this.legs = legs;
this.sound = sound;
this.commonName = commonName;
Mammal.call(this, talk)
}

const lion = new cat(4, 'RAWR', 'Lion');

I want to use talk, with the context of lion.

Upvotes: 0

Views: 63

Answers (1)

joshbang
joshbang

Reputation: 181

You were suuuper close. You just need to add the parameters in the Mammal.call() function.

function Mammal(legs,sound, commonName) {
    this.legs = legs;
    this.sound = sound;
    this.commonName = commonName;
    this.talk = function() {
        return this.sound;
    }
}

const wolf = new Mammal(4, 'GRRRRRR', 'Wolf');

const dog = new Mammal(4, 'WOOF', 'Dog');

const cat = function(legs, sound, commonName) {
    this.legs = legs;
    this.sound = sound;
    this.commonName = commonName;
    Mammal.call(this, legs, sound, commonName);
}

const lion = new cat(4, 'RAWR', 'Lion');

console.log(lion.talk())

I changed Mammal.call(this, talk) to Mammal.call(this, legs, sound, commonName).

I hope this is what you were asking for! Let me know if it isn't.

Edit: I also just noticed that I replaced the console.log() inside of the "talk" function to "return this.sound" and then the very last line I'm doing "console.log(lion.talk())"

Upvotes: 2

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