Reputation: 22405
I found this query that suits my needs thanks to this answer here in order to sort fields of data in a JSON document.
(Fake, generated random data)
SELECT jsonb_agg(elem)
FROM (
SELECT *
FROM jsonb_array_elements('[{
"id": "1",
"first_name": "Maximo",
"last_name": "Sambiedge",
"email": "[email protected]",
"gender": "Male",
"ip_address": "242.145.232.65"
}, {
"id": "2",
"first_name": "Maria",
"last_name": "Selland",
"email": "[email protected]",
"gender": "Female",
"ip_address": "184.174.58.32"
}]') a(elem)
ORDER BY (elem->>'email') -- order by integer value of "ts"
) sub;
As we can see, this works with hardcoded data which doesn't quite fit my needs. I can't seem to figure out how to replace the JSON data with the jsonb column in my table.
My attempt below yields 'data is not defined'
SELECT jsonb_agg(elem), (SELECT data FROM file_metadata)
FROM (
SELECT *
FROM jsonb_array_elements(data) a(elem)
ORDER BY (elem->>'email')
) sub;
My suspicions are that a subquery is needed inside the FROM
clause?
Here is a SQLFiddle of my issue to help describe the table and how the structure is defined: http://sqlfiddle.com/#!17/41102/92
Upvotes: 1
Views: 260
Reputation: 222542
You are almost there. You just need to bring in the original table, like so:
SELECT jsonb_agg(elem)
FROM (
SELECT elem
FROM file_metadata, jsonb_array_elements(data) a(elem)
ORDER BY (elem->>'email')
) sub;
Upvotes: 1