CODEWITHSUNDEEP
python-3.x
Anonitak world
Anonitak world

Reputation: 13

Printing 2 lists on one line

I'm trying to print every first num from each list in one line, I wasted like 1 hour on it trying but didn't the solution

Xx = [1298, 1390, 1487, 1573, 1669, 1766, 1766, 1672, 1573, 1485, 1392, 1297, 1303, 1388, 1487, 1577, 1664, 1757, 1763, 1671,
      1577, 1487, 1393, 1298, 1301, 1376, 1449, 1535, 1604, 1682, 1760, 1769, 1676, 1568, 1485, 1398, 1300]

Yx = [331, 328, 328, 326, 329, 329, 422, 422, 416, 422, 419, 421, 514, 518, 516, 518, 518, 517, 605, 606, 605,
      603, 602, 605, 730, 737, 736, 738, 740, 740, 742, 858, 869, 860, 857, 863, 864]

for posX, posY in (Xx, Yx):
    print(posX, posY)

Error: for posX, posY in (Xx, Yx): ValueError: too many values to unpack (expected 2)

Upvotes: 1

Views: 41

Answers (2)

Om Sao
Om Sao

Reputation: 7673

For iterating simultaneously in multiple list, you need zip(). zip gives a tuple containing the iterators of all the lists given as parameters to it.

Example: 1

l1 = [1, 2, 3]
l2 = [4, 5, 6]
l3 = [7, 8, 9]

for l, m, n in zip(l1, l2, l3):
    print(l, m, n)

Output:

1 4 7
2 5 8
3 6 9

Example: 2

l1 = [1, 2, 3]
l2 = [4, 5, 6]
l3 = [7, 8, 9, 10]
l4 = [11, 12]

for l, m, n, o in zip(l1, l2, l3, l4):
    print(l, m, n, o)

Output:

1 4 7 11
2 5 8 12

Note: that in Example:2 lists l3 and l4 had an unequal number of elements. So, zip iterations are done only till the least number of elements of all the parameters li

Upvotes: 0

san
san

Reputation: 1515

If you intended to print numbers having same index from each list in the row together in one line and so on (going by your attempted code), you need to use zip:

for x, y in zip(Xx, Yx):
    print(x, y)

If you intended to print only the first item of each list (you mentioned something like that)

print(Xx[0], Yx[0])

Upvotes: 1

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