CODEWITHSUNDEEP
javastringchar
chickenWithReis
chickenWithReis

Reputation: 13

Searching the * in a string and replace it through nothing

I have a homework to do and have a problem. I have to search the "*" (star) in a string in Java (I work with Eclipse IDE) and have to delete it, but somehow my Code does not work.

class Main {

    public static String starOut(String s) {
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == '*') {
                s.replace(s.charAt(i), '');

            }
        }

        return s;
    }

    public static void main(String[] args) {
        String result = starOut("ab*cd");
        System.out.println(result); // => "ad"
        System.out.println(starOut("ab**cd")); // => "ad"
        System.out.println(starOut("sm*eilly")); // => "silly"
    }
}

The output should be like in the comments in the last lines

Upvotes: 0

Views: 45

Answers (1)

Elliott Frisch
Elliott Frisch

Reputation: 201467

Your code doesn't even compile, there is no empty char for ''. I would use a StringBuilder, start with an empty StringBuilder and add all char(s) that are not * to it. Then return that as a String. Like,

public static String starOut(String s) {
    StringBuilder sb = new StringBuilder();
    for (int i = 0; i < s.length(); i++) {
        char ch = s.charAt(i);
        if (ch != '*') {
            sb.append(ch);
        }
    }
    return sb.toString();
}

Alternatively, if you can use in-built methods;

public static String starOut(String s) {
    return s.replaceAll("\\*", "");
}

Upvotes: 4

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