CODEWITHSUNDEEP
pythontimeclockdifference
Zerom
Zerom

Reputation: 11

How much time left to given date (days, hours, mins, s.)

I'm trying to make some kind of "deadline clock" in python. There is lot of topics about time difference calculations and I followed some and put together this kind of code:

import datetime
from dateutil.relativedelta import relativedelta

# Get current time:
today = datetime.date.today()
timenow = datetime.datetime.now()
current_time = str(today) + " " + str(timenow.strftime("%H:%M:%S"))

# Set deadline:
deadline = "2019-12-12 15:00:00"

# Calculate difference:
start = datetime.datetime.strptime(current_time,'%Y-%m-%d %H:%M:%S')
ends = datetime.datetime.strptime(deadline, '%Y-%m-%d %H:%M:%S')
diff = relativedelta(ends, start)

print("Now: " + current_time)
print("Deadline: " + deadline)

print(str(diff.days) + " days. " 
      + str(diff.hours) + " hours. " 
      + str(diff.minutes) + " minutes. " 
      + str(diff.seconds) + " seconds. " 
      )

But the problem is, that it will allways show just maximum of one month difference... So where is the problem?

Upvotes: 0

Views: 2796

Answers (1)

Trollsors
Trollsors

Reputation: 492

Just substract your start date with the end date.

import datetime
today = datetime.date.today()
timenow = datetime.datetime.now()
deadline = "2019-12-12 15:00:00"
current_time = str(today) + " " + str(timenow.strftime("%H:%M:%S"))
start = datetime.datetime.strptime(current_time,'%Y-%m-%d %H:%M:%S')
ends = datetime.datetime.strptime(deadline, '%Y-%m-%d %H:%M:%S')

print(start - ends)

As suggested in the comments, you don't really need to to use both .today() and .now() separately, .now() returns the current date and time as a datetime object itself.

import datetime
timenow = datetime.datetime.now().strftime('%Y-%m-%d %H:%M:%S')
deadline = "2019-12-12 00:00:00"
start = datetime.datetime.strptime(timenow,'%Y-%m-%d %H:%M:%S')
ends = datetime.datetime.strptime(deadline, '%Y-%m-%d %H:%M:%S')
print(start - ends)

Upvotes: 1

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