Reputation: 286
I would like to delete an element from a numpy array that has a certain value. However, in the case there are multiple elements of the same value, I only want to delete one occurrence (doesn't matter which one). That is:
import numpy as np
a = np.array([1, 1, 2, 6, 8, 8, 8, 9])
How do I delete one instance of 8? Specifically
a_new = np.delete(a, np.where(a == 8))
print(a_new)
removes all 8's.
Upvotes: 4
Views: 6908
Reputation: 53029
If you know there is at least one 8
you can use argmax
:
np.delete(a,(a==8).argmax())
# array([1, 1, 2, 6, 8, 8, 9])
If not you can still use this method but you have to do one check:
idx = (a==8).argmax()
if a[idx] == 8:
result = np.delete(a,idx)
else: # no 8 in a
# complain
Upvotes: 1
Reputation: 107287
You can simply choose one of the indices:
In [3]: np.delete(a, np.where(a == 8)[0][0])
Out[3]: array([1, 1, 2, 6, 8, 8, 9])
Upvotes: 4