Update a dict values with values in a list

Question

I have a dictionary I want to update:

my_dict = {"a":"A", "b":"B"}

and a list with the exact same length:

my_list = ["D", "E"]

I would like to find the most efficient way to update my_dict with the values from my_list to:

{"a":"D", "b":"E"}

without having to run multiple for loops or similar. I tried to do this with list comprehensions, but it does not allow multiple statements:

{my_dict_key:list_item for my_dict_key in my_dict.keys(), list_item in my_list}

Answer 1

Use zip() with a dictionary-comprehension:

{key: value for key, value in zip(my_dict, my_list)}

Or just:

dict(zip(my_dict, my_list))

Answer 2

May be it will help

1. First find keys by

    keys=dic.keys()

2. Then Update your dictionary with list elements

    for i in range(len(lis)):
        dic[keys[i]]=lis[i] 

3.The Dictionary will be updated.

Answer 3

If you know the order of your dict is the same as the list, you can use a ranged for loop to go through each key.

for i, key in enumerate(dic):
  dic[key] = lis[i]

Demo