CODEWITHSUNDEEP
c++stringintegerconcatenation
pighead10
pighead10

Reputation: 4305

String Concatenation with Integers

Damage and Cost are integers, but as you can see in the code below I want to concatenate them with a string (if that's the right word). How can I do this? 

class Weapon : Shopable{
    private:
        int Damage;
    public:
        std::string getDesc() const{
            return getName()+"\t"+Damage+"\t"+Cost;
        }
};

Upvotes: 0

Views: 1172

Answers (3)

user2100815
user2100815

Reputation:

Provide yourself with this template:

#include <sstream>

template <class TYPE> std::string Str( const TYPE & t ) {
    std::ostringstream os;
    os << t;
    return os.str();
}

You can then say:

return getName() + "\t" + Str( Damage ) + "\t" + Str(Cost);

Note this is pretty much equivalent to Boost's lexical_cast, and to similar facilities in the upcoming standard. Also note that this function trades performance for convenience and type-safety.

Upvotes: 7

AshleysBrain
AshleysBrain

Reputation: 22641

You've already accepted @unapersson's answer, but for the record I would do this...

std::string getDesc() const
{
    std::ostringstream ss;
    ss << getName() << "\t" << Damage << "\t" << Cost;
    return ss.str();
}

It only constructs one stream object instead of creating and throwing them away for each conversion, and it looks a bit nicer too.

(This is the C++ way - there's no general 'toString' member like other languages, generally we use string streams or a one-off function like in @unapersson's answer.)

Upvotes: 2

Kirill V. Lyadvinsky
Kirill V. Lyadvinsky

Reputation: 99695

You could use boost::lexical_cast as follows:

return getName()+"\t"+boost::lexical_cast<std::string>(Damage)+
  "\t"+boost::lexical_cast<std::string>(Cost);

Upvotes: 2

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