Reputation: 419
I want to count occurrences of Number 3 from multiple columns with group by Primary Key. I have a table like this.
And I have tried with this.
But my output is
But expected output is something like this
Upvotes: 0
Views: 592
Reputation: 84
SELECT id, ( SUM(CASE WHEN s1 =3 THEN 1 ELSE 0 END ) + SUM(CASE WHEN s2 =3 THEN 1 ELSE 0 END ) +
SUM(CASE WHEN s3 =3 THEN 1 ELSE 0 END ) +
SUM(CASE WHEN s4 =3 THEN 1 ELSE 0 END ) +
SUM(CASE WHEN s5 =3 THEN 1 ELSE 0 END ) ) AS val FROM t1 GROUP BY id
I think it will be helpful for you
Upvotes: 0
Reputation: 238086
Your query only counts rows with multiple threes one time.
You could use a union:
select id
, sum(case when val = 3 then 1 else 0 end)
from (
select id, s1 as val from t1
union all select id, s2 from t1
union all select id, s3 from t1
union all select id, s4 from t1
union all select id, s5 from t1
) sub
group by
id
Upvotes: 1
Reputation: 339
Try Below Query..
select id,(count(s1)+count(s2)+count(s3)+count(s4)+count(s5))valcount from(
select id, case when s1=3 then 1 end as s1,
case when s2=3 then 1 end as s2,
case when s3=3 then 1 end as s3,
case when s4=3 then 1 end as s4,
case when s5=3 then 1 end as s5
from test) group by id
and Try another way
select id,
count(decode(s1,3,1))+
count(decode(s2,3,1))+
count(decode(s3,3,1))+
count(decode(s4,3,1))+
count(decode(s5,3,1))valcount
from test
group by id
Upvotes: 1
Reputation: 164099
With this:
select id,
(s1 = 3) + (s2 = 3) + (s3 = 3) + (s4 = 3) + (s5 = 3) valcount
from tablename
Each of the boolean expressions:
s? = 3
evaluates to 0
or 1
.
Upvotes: 2