Reputation: 121
I have as input the string in the below format
"[1_5,3,7,1],[1_2,4,1,9],[],[1_1,,4,,,9,2]"
What I need to obtain is the same string but with the number after the _
sorted:
"[1_1,3,5,7],[1_1,2,4,9],[],[1_1,2,4,9,,,]"
Dim tmprequestedArea_selectionAreaIn As String = "[1_5,3,7,1],[1_2,4,1,9],[],[1_1,,4,,,9,2]"
tmprequestedArea_selectionAreaIn = Regex.Replace(requestedArea_selectionAreaIn,"\],\[","#")
tmprequestedArea_selectionAreaIn = Regex.Replace(tmprequestedArea_selectionAreaIn,"\[|\]","")
bracList.AddRange(tmprequestedArea_selectionAreaIn.Split(New Char() {"#"c}, StringSplitOptions.None ))
If sortNumber Then
'Split braclist by _ and puts the value in strList
'If after _ is only one number put only that number, else split it by char "," and put in strList the join of the split by , array
'Sort the array
'in previous example strList will contain a,b,c in position 0 and _d_f (instead of f,d) in position 1
For i As Integer = 0 To bracList.Count -1
Dim tmp As String()
Dim tmpInt As New System.Collections.Generic.List(Of Integer)
If Not(String.IsNullOrEmpty(bracList(i))) Then
Dim tmpRequested As String = bracList(i).Split(New Char() {"_"c})(0)
Dim tmpSelection As String = bracList(i).Split(New Char() {"_"c})(1)
If tmpSelection.Contains(",") Then
tmp = tmpSelection.Split(New Char() {","c})
For j As Integer = 0 To tmp.Length -1
tmpInt.Add(Convert.toInt32(tmp(j)))
Next
tmpInt.Sort
strList.Add("[" + tmpRequested + "_" + String.Join(",",tmpInt ) + "]")
Else
strList.Add("[" + tmpRequested + "_" + tmpSelection + "]" )
End If
Else
strList.Add("[]")
End If
Next i
I'm looking for a better way to manage it.
Upvotes: 1
Views: 125
Reputation: 32248
Try this, as a possible substitute for what you're doing now.
Given this input string:
Dim input As String = "[1_5,3,7,1],[1_2,4,1,9],[],[1_1,,4,,,9,2]"
Note: this will also deal with decimal values without changes. E.g.,
"[1_5.5,3.5,7,1],[1_2.564,4,2.563,9],[],[1_1,,4.23,,,9.0,2.45]"
You can extract the content of the brackets with this pattern: \[(.*?)\]
and use Regex.Matches to return a MatchCollection of all the substrings that match the pattern.
Then use a StringBuilder as a container to rebuild the string while the parts are being treated.
Imports System.Linq
Imports System.Text.RegularExpressions
Dim pattern As String = "\[(.*?)\]"
Dim matches = Regex.Matches(input, pattern, RegexOptions.Singleline)
Dim sb As New StringBuilder()
For Each match As Match In matches
Dim value As String = match.Groups(1).Value
If String.IsNullOrEmpty(value) Then
sb.Append("[],")
Continue For
End If
Dim sepPosition As Integer = value.IndexOf("_"c) + 1
sb.Append("[" & value.Substring(0, sepPosition))
Dim values = value.Substring(sepPosition).Split(","c)
sb.Append(String.Join(",", values.Where(Function(n) n.Length > 0).OrderBy(Function(n) CDec(n))))
sb.Append(","c, values.Count(Function(n) n.Length = 0))
sb.Append("],")
Next
Dim result As String = sb.ToString().TrimEnd(","c)
If you don't know about LINQ, this is what it's doing:
String.Join(",", values.Where(Function(n) n.Length > 0).OrderBy(Function(n) CDec(n)))
values
is an array of strings, generated by String.Split()
.
values.Where(Function(n) n.Length > 0)
: creates an Enumerable(Of String)
from values
Where
the content, n
, is a string of length > 0
.
I could have written values.Where(Function(n) Not String.IsNUllOrEmpty(n))
.
.OrderBy(Function(n) CDec(n)))
: Orders the resulting Enumerable(Of String)
using the string value converted to Decimal and generates an Enumerable(Of String)
, which is passed back to String.Join()
, to rebuild the string, adding a char (","c
) between the parts.
values.Count(Function(n) n.Length = 0)
: Counts the elements of values
that have Length = 0
(empty strings). This is the number of empty elements that are represented by a comma, appended at the end of the partial string.
Upvotes: 3