CODEWITHSUNDEEP
linuxsed
Ricky
Ricky

Reputation: 15

How can I increment a number in a sub part of a string using sed command? and the input will be changed dynamically

I would like to increment sub part of string version="01.00.00.041" by 1 using sed. For example: version="01.00.00.041" to version="01.00.00.042" and it should be dynamic not static. I mean, the version number will be changed everytime when I build, so it should be an input to the sed and last 1 digit should be incremented.

Edit: (collected from the comment)
I have tried like below: 

sed -i "s/version.*/version=\"${print $ "."$ "."$ "."$ +1}}\">/g" descriptor.xml

Upvotes: 0

Views: 1000

Answers (2)

RavinderSingh13
RavinderSingh13

Reputation: 133458

EDIT: Since OP added an information so adding code as per information.

awk -v version="version=\"01.00.00.42\"" 'BEGIN{FS=OFS=".";s1="\""} match($0,version) && ++count==2{$NF+=1;$NF=$NF s1} 1' Input_file

Here is the working solution Added by OP:

grep version descriptor.xml | tail -n 1 | awk -F= '{print $2}' | awk -F\" '{print $2}' increatedNum=$(printf "%03d" expr $(echo $OldVersion | cut -d'.' -f4) + 1) NewVersion=echo $OldVersion | cut -d'.' -f1-3.$increatedNum sed -i "s/$OldVersion/$NewVersion/g" descriptor.xml

Could you please try following.

awk 'BEGIN{FS=OFS=".";s1="\""} {$NF+=1;$NF=$NF s1} 1'  Input_file

Output will be as follows.

version="01.00.00.42"

In case you want to save output into Input_file itself use following then.

awk 'BEGIN{FS=OFS=".";s1="\""} {$NF+=1;$NF=$NF s1} 1' Input_file > temp && mv temp Input_file

OR as per @tshiono's comment you could try following too.

awk 'BEGIN{FS=OFS=".";s1="\""} {$NF+=1;$NF=sprintf("%03d%c", $NF, s1)} 1' Input_file

Upvotes: 1

Shawn
Shawn

Reputation: 52344

With perl:

$ echo 'version="01.00.00.041"' | perl -pe 's/(\d+)(?=")/sprintf("%0*d", length($1), $1+1)/e'
version="01.00.00.042"

Increments the last set of digits before a quote, with 0 padding based on the length of the field instead of a hardcoded number.

Upvotes: 2

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