Reputation: 85
I am trying to style a website using a stylesheet.css file.
In one of my html pages, I have the <link rel="stylesheet" href="stylesheet.css">
element. The css file is in my templates folder (image):
When I start the application and go to a page, The console reads:
"GET /home/stylesheet.css HTML 1.1/" 200
But the page doesn't appear to load correctly (meaning none of the CSS settings are applied). I am using repl.it to run this website.
Here is the link to the repl: sm--supermechm500.repl.it [REPL.IT]
Here is my css file:
@import url('https://fonts.googleapis.com/css?family=Aldrich&display=swap');
body {
align-items: center;
text-align: center;
background-color: #000000;
width: auto;
height: auto;
font-family: 'Aldrich', sans-serif;
}
I have already reviewed this question: Application not picking up css file , but I didn't quite understand the answer provided, or the question's code.
What is the proper way to make flask render a page using a stylesheet?
Upvotes: 2
Views: 826
Reputation: 1
To be more specific, actual solution is
href="{{ url_for('static', filename='stylesheet.css') }}"
to href="{{ url_for('static', filename='css/stylesheet.css') }}"
ORhref="../static/main.css" to href="../static/css/main.css"
Upvotes: 0
Reputation: 85
After some research, I found that I have done it all wrong.
I needed a "static" folder in my directory, in which is another folder named "css". In that folder is the stylesheet.css
/ = folder
main.py
/templates
pages.html
/static
/css
stylesheet.css
other_files.txt
And within the html, replace<link rel="stylesheet" href="stylesheet.css">
with<link rel="stylesheet" href="{{ url_for('static', filename='css/stylesheet.css') }}">
And just a note, just because the console says status code "200" FOUND doesn't mean it was loaded, or loaded correctly.
Upvotes: 3