CODEWITHSUNDEEP
javaandroidarrayskotlin
RIKI
RIKI

Reputation: 13

Is it possible to create a ByteArray of ByteArrays as elements in kotlin?

I have some issues with creating a ByteArray var where its elements are also ByteArray, I don't know is it possible first ? and how to ?

Upvotes: 1

Views: 4929

Answers (2)

Quinn
Quinn

Reputation: 9434

A ByteArray is just what it sounds like, an array of bytes. If you want to hold onto multiple byte arrays you can use a generic list or array.

Something like this:

// say you have three byte arrays
val ba1 = ByteArray(3) { it.toByte() }
val ba2 = ByteArray(3) { (it + 3).toByte() }
val ba3 = ByteArray(3) { (it + 6).toByte() }

// make a list of them like so
val allByteArray = listOf(ba1, ba2, ba3)

Based on your more recent comment it seems you may want to add to allByteArray in a loop, if that is the case you can also use an ArrayList like this:

val allByteArray = ArrayList<ByteArray>()
for (i in 0 until 3) {
    // some byte array
    val ba = ByteArray(3) { (it + (i*3)).toByte() }

    // add to list
    allByteArray.add(ba)
}

Also as suggested by Alexey Romanov, you could do this in the constructor for a MutableList (or the same thing can be done with a list if it doesn't need to be mutable) like this:

val allByteArray = MutableList(3) { i ->
    ByteArray(3) { (it + (i*3)).toByte() }
}

Upvotes: 3

Tenfour04
Tenfour04

Reputation: 93609

Maybe you're looking for a 2D array of Bytes? You can create an Array of ByteArrays:

val array = Array(3){ByteArray(3)}
array[0][1] = 3 // for example

or to initialize it as you declare it:

val array = arrayOf(
    byteArrayOf(0, 1, 2),
    byteArrayOf(3, 4, 5),
    byteArrayOf(6, 7, 0)
)

In Java this would be:

byte[][] array = new byte[3][3];
// or
byte[][] array = {
    {0, 1, 2},
    {3, 4, 5},
    {6, 7, 0},
}

Upvotes: 2

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