CODEWITHSUNDEEP
pythonpython-3.7
Christian R
Christian R

Reputation: 313

Calculating Tuition Cost Increase Over 5 Years

Still very new to Python programming and learning the basics, any help is greatly appreciated.

#Define Variables
# x= starting tuition
# y= tuition increae per year
# z = new tuition

#List known Variables
cost = int(25000)
increase = float(.025)

#Calculate the tuiton increase
tuition = cost * increase

 #Calculate the cost increase over 5 years
 #Initialize accumulator for test scores.
total = int(25000)
for x in range(5):
    print('$', format(total+tuition, ',.2f'), sep='')

Output should be similar to: Year 1: $25,000 Year 2: $25,625 Year 3: $26,276.63 Year 4: $26,933.54 Year 5: $27,606.88

I am having trouble writing the script so that there is a 2% increase added onto $25,000, then 2% onto $25,625, then 2% increase to equal $26,276.63 etc. etc. for 5 years.

Thank you for the help!

Upvotes: 2

Views: 2203

Answers (4)

Tula Magar
Tula Magar

Reputation: 141

replace the increased value which is %

            #Define Variables
            # x= starting tuition
            # y= tuition increae per year
            # z = new tuition

            #List known Variables
            cost = int(25000)
            increase = float(0.02)

            #Calculate the tuiton increase
            tuition = cost * increase
            #Calculate the cost increase over 5 years
            #Initialize accumulator for test scores.
             total = int(25000)

             count = 1


       """use this to print in new line"""
            for x in range(5):

            print('year {}: ${} ' .format(count, total + count * tuition, ',.2f'), sep='')

           count = count + 1

"""use this to print in same line"""
         for x in range(5):

         print('year {}: ${}, ' .format(count, total + count * tuition, ',.2f'), end='')

         count = count + 1

Upvotes: 0

Waqar Bin Kalim
Waqar Bin Kalim

Reputation: 321

What you're wanting to do is basically compound interest and the formula for that would be cost * (1+increase)^n where n would be the number of years so far

  • So Year 0 25000 * (1+0.025)^0 = 25000
  • So Year 1 25000 * (1+0.025)^1 = 25625
  • So Year 2 25000 * (1+0.025)^2 = 26265.62
  • So Year 3 25000 * (1+0.025)^3 = 26922.27
  • So Year 4 25000 * (1+0.025)^4 = 27595.32
cost = int(25000)
increase = float(.025)

for x in range(5):
    tuition = cost*((1.000+increase)**x)
    print(str(x) + ': $', format(tuition, ',.2f'), sep='')

Hope this helps!!

Upvotes: 0

Sayandip Dutta
Sayandip Dutta

Reputation: 15872

You are just printing same value (increase in ) over and over. Try this:

cost = int(25000)
increase = float(1.025)

#Calculate the tuiton increase


 #Calculate the cost increase over 5 years
 #Initialize accumulator for test scores.
total = cost
print('Year 1: ${0:,.2f}'.format(total), end = ' ')
for x in range(2,6):
    total = total*increase
    print('Year {0}: ${1:,.2f}'.format(x,total), end=' ')

Upvotes: 0

elembie
elembie

Reputation: 640

Good choice on python! A few basics...

You don't need to tell python what type your variables are, you just initialise them and python interprets at run time;

cost = 25000
increase = 0.025

Aside from that your logic/maths seems a little off - as mentioned in the comments you should be recalculating the tuition inside the loop, as the % increase depends on the previous year. 

cost = 25000
increase = 1.025

print(cost)

for i in range(5)
  cost = cost * increase
  print(f'${str(cost)}')

Multiplying by 1.025 is the same as saying 'add 2.5% to the current value'. I'm using a formatted string to print (the f before the string says that) - you can put variables or expressions inside the {}, as long as they output strings (hence the str(cost) which converts the cost to a string to print).

Upvotes: 1

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