CODEWITHSUNDEEP
powershellazure-devops
Nathan
Nathan

Reputation: 915

Azure DevOps Rest API in Powershell saying no parameters matching

I am starting to use PowerShell to call the Azure DevOps REST API. But it seems like when I try to add parameters it tell me:

A parameter cannot be found that matches parameter name 'repositoryId'

Here is what my call looks like in PowerShell. If I take out the parameter it works. What am I doing wrong?

Invoke-RestMethod -Uri 'https://dev.azure.com/{organization}/{project}/_apis/build/builds?api-version=5.1' -repositoryId $repoId -Headers (my authentication) -Method Get

Per Microsoft's documentation this should work. https://learn.microsoft.com/en-us/rest/api/azure/devops/build/builds/list?view=azure-devops-rest-5.1

Upvotes: 1

Views: 1615

Answers (2)

Levi Lu-MSFT
Levi Lu-MSFT

Reputation: 30353

repositoryId should be url parameter as Booga Roo mentioned. The error indicated that Repository type is missing.

You should add another parameter to your uri repositoryType={repositoryType}.So the uri should be like below.

Please check here for all repositoryTypes

https://dev.azure.com/{Organization}/{Project}/_apis/build/builds?repositoryId={id}&repositoryType=TfsGit&api-version=5.1

Addition:

You can get your repositoryId from URL of Repositories page under Repos in the Project Settings. Check below screentshot.

enter image description here

Upvotes: 2

Booga Roo
Booga Roo

Reputation: 1781

The Invoke-RestMethod cmdlet does not have a -repositoryId parameter. The phrasing and examples on the help page are for "URI Parameters" instead of PowerShell parameters. It means you need to build it into -Uri value instead of trying to use it directly.

I suggest using this:

Invoke-RestMethod -Uri "https://dev.azure.com/{organization}/{project}/_apis/build/builds?repositoryId={$repoId}&api-version=5.1" -Headers (my authentication) -Method Get

Side note: There are double quotes around this example URI. This is so the variable expansion for $repoId will occur and be properly interpreted as part of the URI. Using single quotes as in the original example will prevent this and treat it as a literal string value and won't perform any subsitutions.

Upvotes: 1

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