CODEWITHSUNDEEP
c++arrays
Robert Lennon
Robert Lennon

Reputation: 1

Passing char as argument

int sk03(char * a)   //DELETE! DELEEEEETE!
{                      //(Or "Exterminate! EXTERMINAAAAAATE!" if that's your thing.)
    int b = sk00(a);
    int c = 0;
    while(a[b] != '!')
    {
        a[c] = a[b];
        c++;b++;
    }
    cout << a << "\n";
    int your_mom = 0;
    return your_mom;
}

int main()
{
    char * str = "``sk`sk!";
    return sk03(str);
}

This method works fine for when you want to pass the entire string to the function, but how would one pass just the second half of the string to sk03? Would I have to create a complete new array?

Upvotes: 0

Views: 5305

Answers (3)

Heisenbug
Heisenbug

Reputation: 39164

for example you can modify your code to do something like this:

char  str[STRING_LENGTH] = "``sk`sk!";
return sk03(&str[3]);

Upvotes: 1

Draco Ater
Draco Ater

Reputation: 21226

Pass it like

char * str = "``sk`sk!";
return sk03(&str[4]);

Upvotes: 1

user2100815
user2100815

Reputation:

No, you just pass a pointer to the element you want:

char a[100];
sk03( a + 50 );     // call function passing second half of the array

Upvotes: 1

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