CODEWITHSUNDEEP
django-views
rajkumar
rajkumar

Reputation: 115

Using multiple forms on a page in Django

How do I use more than one form per page in Django?

Upvotes: 9

Views: 27884

Answers (2)

Daniel Sokolowski
Daniel Sokolowski

Reputation: 12448

Judging by the date of your questions I am going to assume you are using class based views, below is copied from my other answer here: Proper way to handle multiple forms on one page in Django

class NegotiationGroupMultifacetedView(TemplateView):
    ### TemplateResponseMixin
    template_name = 'offers/offer_detail.html'

    ### ContextMixin 
    def get_context_data(self, **kwargs):
        """ Adds extra content to our template """
        context = super(NegotiationGroupDetailView, self).get_context_data(**kwargs)

        ...

        context['negotiation_bid_form'] = NegotiationBidForm(
            prefix='NegotiationBidForm', 
            ...
            # Multiple 'submit' button paths should be handled in form's .save()/clean()
            data = self.request.POST if bool(set(['NegotiationBidForm-submit-counter-bid',
                                              'NegotiationBidForm-submit-approve-bid',
                                              'NegotiationBidForm-submit-decline-further-bids']).intersection(
                                                    self.request.POST)) else None,
            )
        context['offer_attachment_form'] = NegotiationAttachmentForm(
            prefix='NegotiationAttachment', 
            ...
            data = self.request.POST if 'NegotiationAttachment-submit' in self.request.POST else None,
            files = self.request.FILES if 'NegotiationAttachment-submit' in self.request.POST else None
            )
        context['offer_contact_form'] = NegotiationContactForm()
        return context

    ### NegotiationGroupDetailView 
    def post(self, request, *args, **kwargs):
        context = self.get_context_data(**kwargs)

        if context['negotiation_bid_form'].is_valid():
            instance = context['negotiation_bid_form'].save()
            messages.success(request, 'Your offer bid #{0} has been submitted.'.format(instance.pk))
        elif context['offer_attachment_form'].is_valid():
            instance = context['offer_attachment_form'].save()
            messages.success(request, 'Your offer attachment #{0} has been submitted.'.format(instance.pk))
                # advise of any errors

        else 
            messages.error('Error(s) encountered during form processing, please review below and re-submit')

        return self.render_to_response(context)

The html template is to the following effect:

...

<form id='offer_negotiation_form' class="content-form" action='./' enctype="multipart/form-data" method="post" accept-charset="utf-8">
    {% csrf_token %}
    {{ negotiation_bid_form.as_p }}
    ...
    <input type="submit" name="{{ negotiation_bid_form.prefix }}-submit-counter-bid" 
    title="Submit a counter bid"
    value="Counter Bid" />
</form>

...

<form id='offer-attachment-form' class="content-form" action='./' enctype="multipart/form-data" method="post" accept-charset="utf-8">
    {% csrf_token %}
    {{ offer_attachment_form.as_p }}

    <input name="{{ offer_attachment_form.prefix }}-submit" type="submit" value="Submit" />
</form>

...

Upvotes: 5

Herman Schaaf
Herman Schaaf

Reputation: 48425

Please see the following previously asked (and answered) questions:

Django: multiple models in one template using forms

and

Proper way to handle multiple forms on one page in Django.

Depending on what you're really asking, this is my favorite way to handle different models on the same page:

if request.POST():
    a_valid = formA.is_valid()
    b_valid = formB.is_valid()
    c_valid = formC.is_valid()
    # we do this since 'and' short circuits and we want to check to whole page for form errors
    if a_valid and b_valid and c_valid:
        a = formA.save()
        b = formB.save(commit=False)
        c = formC.save(commit=False)
        b.foreignkeytoA = a
        b.save()
        c.foreignkeytoB = b
        c.save()

Upvotes: 17

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