Reputation: 313
i have a huge collection of data 700+ items in, and i want to filter by dynamic array of objects, lets say that user has typed ode
and my script should search on every filter without i do something like filter.code == store.code
const hugeData = [{name:"store 1",code : "code 1", available : false},{name : "store 2",code : "simple_code",available : true},{name : "sto 3",code : "has no cde",available : true}...]
const filters = [{ code : "ode", name : "re" }]
the result that im expecting is
// output
[{name : "store 1", code : "code 1", available : false},{name : "store 2",code : "simple_code",available : true}]
i resolved this doing the following with lodash
, but function is very slow, and code is poor, is there any other way that i can do this works?
const results = []
_.map(hugeData, store => {
_.map(filters, tag => {
Object.keys(tag).map(tagOb => {
if (store[tagOb] && store[tagOb].includes(tag[tagOb])) {
results.push(store);
}
});
});
});
Upvotes: 1
Views: 489
Reputation: 6482
This might be faster - storing the Object.keys()
result, and filtering out any keys that aren't on the first store (assuming all stores are equivalent). I also used a single object for filters
.
const hugeData = [
{ name: "store 1", code: "code 1", available: false },
{ name: "store 2", code: "simple_code", available: true },
{ name: "sto 3", code: "has no cde", available: true }
];
const filters = { code: "ode", name: "re" };
const keys = Object.keys(filters).filter(k => hugeData[0].hasOwnProperty(k));
console.log(
hugeData.filter(s => keys.some(k => s[k].includes(filters[k])))
);
If you wanted ALL filters, to match, you could change it to every
:
hugeData.filter(s => keys.every(k => s[k].includes(filters[k])))
Upvotes: 0
Reputation: 37755
You can use filter
and some
const hugeData = [{ name: "store 1", code: "code 1",available: false}, { name: "store 2", code: "simple_code",available: true}, { name: "sto 3", code: "has no cde", available: true }]
const filters = { code: "ode", name: "re" }
let final = hugeData.filter(value => {
return Object.entries(value).some(([key, value]) => {
return typeof value == 'string' && value.includes(filters[key])
})
})
console.log(final)
Upvotes: 3