CODEWITHSUNDEEP
pythonpython-3.xlogging
binny
binny

Reputation: 729

Logger instance doesn't return any log records

This is a scenario where a module contains a Logger and it is being imported into another module. When main.py is called however, no LogRecords are written to the log. What can be revised in order for the log to be called?

#objects.py

import logging

logger = logging.getLogger(__name__)
logger.setLevel(logging.INFO)

formatter = logging.Formatter()

log_handler = logging.FileHandler('log_objects.log')
log_handler.setFormatter(formatter)
logger.addHandler(log_handler)

class Person:
    def __init__(self):
        pass

        logger.info(f"A new {self.__class__.__name__} is created.")

#main.py

from my_objects import objects

if __name__ == '__main__':
    objects.Person()

-dir/
    -my_objects/
        __init__.py
        log_objects.log
        objects.py

    -main.py

I'm expecting to see this in the log: "A new Person is created."

Upon execution nothing shows in the log

Upvotes: 0

Views: 33

Answers (2)

Vivek
Vivek

Reputation: 21

It works as expected. 'log_objects.log' is got created with valid line. Are you expecting the text to be printed on the console as well? Once specific file handler is added the default handler will be overwritten.

(or) You possibly missing that how module load happens in python


$ python main.py

$ tree .
.
├── log_objects.log
├── main.py
└── my_objects
    ├── __init__.py
    └── objects.py


$ cat log_objects.log
A new Person is created.

Upvotes: 0

blhsing
blhsing

Reputation: 106553

Since you do not specify a path name for log_objects.log, the file will be created under the directory where the Python interpreter is run, which in this case, is where main.py is located, rather than under the my_objects sub-directory.

If you want log_objects.log to be created under the my_objects directory, you can specify a relative path:

log_handler = logging.FileHandler('my_objects/log_objects.log')

Upvotes: 1

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