CODEWITHSUNDEEP
pythonpython-3.x
powerPixie
powerPixie

Reputation: 708

Open directory and read distinct files and save them into distinct variables, Python

I am working with this list of files in a local directory:

docs = ['5d7d3c905deeb7978034cb40.txt','5d7d3c905deeb7978034cb40.txt','5d7d26ae5deeb7978034cab3.txt',
        '5d7d268e5deeb7978034cab2.txt','5dac3ad15deeb749fcbbfeab.txt']

If I do this:

for doc in docs:

   for txt in open(doc):

I manage to open and read the texts all together. But I want to get each one of them into a distinct variable.

My best solution, for now, is this one:

abstracts = []

for i in range(len(docs)):

   for doc in docs:

      for txt in open(doc):

          txs = [txt] #each text 

          if txs not in abstracts:
             abstracts.append(txs)

I can reach the txs I want by the use of indexes, but I am sure there must be a better way to do this.

Upvotes: 0

Views: 187

Answers (3)

Nicolas Gervais
Nicolas Gervais

Reputation: 36714

globals()["name_of_your_variable"] = my_variable will assign a variable based on the string you give it. It should work if you str.split(doc, ".")[0] it first to remove the period.

Upvotes: 0

kaki gadol
kaki gadol

Reputation: 1380

I would use a dictionary which the keys are the files' names and and values are the files' content

files = {}
for doc in docs:
    with open(doc, 'r') as f:
        files[doc] = f.read()

Upvotes: 1

bigbounty
bigbounty

Reputation: 17408

Instead use a dict in python.

import os

content_dict = {}

for f_name in os.listdir("."):
    content_dict[f_name.split(".")[0]] = open(f_name).read()

print(content_dict)

Upvotes: 1

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