Reputation: 1159
Im stuck in saving this for loop results, I've searched in stack all kind to save output of the for loop but I did come a the right solution. My code is:
doc = sys.argv[1]
target = sys.argv[2]
fene = int(sys.argv[3])
a = open(file)
text = a.read()
a.close()
tokens = text.split()
keyword = re.compile(target, re.IGNORECASE)
for index in range( len(tokens) ):
if keyword.match( tokens[index] ):
start = max(0, index-window)
finish = min(len(tokens), index+window+1)
lhs = " ".join( tokens[start:index] )
rhs = " ".join( tokens[index+1:finish] )
print("%s \t \t %s \t \t %s" % (lhs, tokens[index], rhs))
I tried
f = open("output.txt", w)
then at the end(line print) i've added f.write(lsm, tokens[index], rhs)
this did not work. Even bringing open() into for loop.
How too handle it?
UPDATE: output of for loop that I want in txt.
Upvotes: 2
Views: 596
Reputation: 1159
@Michael answer explanation in comment. Thanks
saveme = open('output.txt', 'w')
for index in range( len(tokens) ):
if keyword.match( tokens[index] ):
start = max(0, index-window)
finish = min(len(tokens), index+window+1)
lhs = " ".join( tokens[start:index] )
rhs = " ".join( tokens[index+1:finish] )
print("%s \t \t %s \t \t %s" % (lhs, tokens[index], rhs), file=saveme)
saveme.close()
Upvotes: 1