Reputation: 9063
I have an ImageButton control as part of a GridView control that is displayed as an ItemTemplate and in the same GridView. I have a regular Button control to which I added some code like this
if (e.CommandName == "addToSession")
{
int index = Convert.ToInt32(e.CommandArgument);
GridViewRow selectedRow = ((GridView)e.CommandSource).Rows[index];
string ISBN = selectedRow.Cells[0].Text;
string bookTitle = selectedRow.Cells[1].Text;
string image = selectedRow.Cells[2].Text;
//storing title, author, pictureUrl into session variables to 'carry them over' to RateBook.aspx
Service s = new Service();
Session["ISBN"] = ISBN;
Session["bookTitle"] = bookTitle;
Session["ImageUrl"] = s.returnImageUrl(bookTitle);
if (Session["userName"] == null)
{
Response.Redirect("registerPage.aspx");
}
else
{
Response.Redirect("RateBook.aspx");
}
}
else if (e.CommandName == "ratedBooks")
{
int index = Convert.ToInt32(e.CommandArgument);
GridViewRow selectedRow = ((GridView)e.CommandSource).Rows[index];
string bookTitle = selectedRow.Cells[1].Text;
Service s = new Service();
Session["ImageUrl"] = s.returnImageUrl(bookTitle);
Response.Redirect("BookRated.aspx");
}
when I run this code I get a format exception and again I am not sure why. I have altered the image button a bit and nested the image in a link button which seems to be more correct.
<asp:TemplateField>
<ItemTemplate>
<asp:LinkButton ID="LinkButton1" runat="server" CommandName="ratedBooks">
<asp:Image ID="ImageButton1" ImageUrl='<%#Eval("pictureUrl") %>' runat="server" />
</asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
Please advise.
Regards,
Arian
Upvotes: 0
Views: 3254
Reputation: 1334
You need CommandArgument
<asp:TemplateField ShowHeader="False">
<ItemTemplate>
<asp:ImageButton ID="ImageButton1" runat="server" CommandName="Delete" CommandArgument="<%# ((GridViewRow) Container).RowIndex %>" ImageUrl="~/Modelos/Img/deleted.gif" />
</ItemTemplate>
</asp:TemplateField>
code behind C#
public void GridView_RowCommand(Object sender, GridViewCommandEventArgs e)
{
string t;
if (e.CommandName == "Delete")
{
int index = Convert.ToInt32(e.CommandArgument);
GridViewRow selectedRow = grid1.Rows[index];
t = selectedRow.Cells[2].Text;
}
}
On ASPX
<asp:GridView ID="grid1" runat="server" onselectedindexchanged="GridView1_SelectedIndexChanged" ...
Upvotes: 0
Reputation: 25692
I believe you can accomplish your needs with an ImageButton
, as it supports all the major Button
functionality, including CommandName
(see http://msdn.microsoft.com/en-us/library/system.web.ui.webcontrols.imagebutton.commandname.aspx).
Try this out:
<asp:ImageButton ID="LinkButton1" runat="server"
CommandName="ratedBooks"
ImageUrl='<%#Eval("pictureUrl") %>' />
Also, note that your format exception could be coming from the lines that read:
Convert.ToInt32(e.CommandArgument);
The reason being that there appears from this code snippet to be no value assigned to the CommandArgument of the button. Convert.ToInt32
requires a valid integer value to be passed in, which means that the ImageButton
needs to have a number bound to its CommandArgument
property.
If you based your solution on this MSDN reference (http://msdn.microsoft.com/en-us/library/system.web.ui.webcontrols.gridviewcommandeventargs.aspx), note that the <asp:ButtonField>
column type gets special treatment; the CommandArgument
is set to the row index. When you use a template field, ASP.NET requires you to specify or data bind your own command argument.
Update
This question contains details on binding the grid view row index to a custom button:
ASP.NET GridView RowIndex As CommandArgument
Upvotes: 1
Reputation: 505
A possible solution is to add the ItemDataBound event handler and search for the image button change its image url.
MyGrid.RowDataBound += new RepeaterItemEventHandler(MyGrid_RowDataBound);
void MyGrid_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowIndex > -1)
{
ImageButton image = e.Row.FindControl("MY_IMAGE_CONTROL") as ImageButton;
image.ImageUrl = "PATH_TO_IMAGE";
}
}
Hope it helps.
Upvotes: 1