Reputation: 178
I have a dataframe:
+--------------------+------+
|people |person|
+--------------------+------+
|[[jack, jill, hero]]|joker |
+--------------------+------+
It's schema:
root
|-- people: struct (nullable = true)
| |-- person: array (nullable = true)
| | |-- element: string (containsNull = true)
|-- person: string (nullable = true)
Here, root--person is a string. So, I can update this field using udf as:
def updateString = udf((s: String) => {
"Mr. " + s
})
df.withColumn("person", updateString(col("person"))).select("person").show(false)
output:
+---------+
|person |
+---------+
|Mr. joker|
+---------+
I want to do same operation on root--people--person column which contains array of person. How to achieve this using udf?
def updateArray = udf((arr: Seq[Row]) => ???
df.withColumn("people", updateArray(col("people.person"))).select("people").show(false)
expected:
+------------------------------+
|people |
+------------------------------+
|[Mr. hero, Mr. jack, Mr. jill]|
+------------------------------+
Edit: I also want to preserve its schema after updating root--people--person.
Expected schema of people:
df.select("people").printSchema()
root
|-- people: struct (nullable = false)
| |-- person: array (nullable = true)
| | |-- element: string (containsNull = true)
Thanks,
Upvotes: 3
Views: 1997
Reputation: 27373
The problem here is that people
is s struct with only 1 field. In your UDF, you need to return Tuple1
and then further cast the output of your UDF to keep the names correct:
def updateArray = udf((r: Row) => Tuple1(r.getAs[Seq[String]](0).map(x=>"Mr."+x)))
val newDF = df
.withColumn("people",updateArray($"people").cast("struct<person:array<string>>"))
newDF.printSchema()
newDF.show()
gives
root
|-- people: struct (nullable = true)
| |-- person: array (nullable = true)
| | |-- element: string (containsNull = true)
|-- person: string (nullable = true)
+--------------------+------+
| people|person|
+--------------------+------+
|[[Mr.jack, Mr.jil...| joker|
+--------------------+------+
Upvotes: 1
Reputation: 1892
for you just need to update your function and everything remains the same. here is the code snippet.
scala> df2.show
+------+------------------+
|people| person|
+------+------------------+
| joker|[jack, jill, hero]|
+------+------------------+
//jus order is changed
I just updated your function instead of using Row I am using here Seq[String]
scala> def updateArray = udf((arr: Seq[String]) => arr.map(x=>"Mr."+x))
scala> df2.withColumn("test",updateArray($"person")).show(false)
+------+------------------+---------------------------+
|people|person |test |
+------+------------------+---------------------------+
|joker |[jack, jill, hero]|[Mr.jack, Mr.jill, Mr.hero]|
+------+------------------+---------------------------+
//keep all the column for testing purpose you could drop if you dont want.
let me know if you want to know more about same.
Upvotes: 1
Reputation: 812
Let's create data for testing
scala> val data = Seq((List(Array("ja", "ji", "he")), "person")).toDF("people", "person")
data: org.apache.spark.sql.DataFrame = [people: array<array<string>>, person: string]
scala> data.printSchema
root
|-- people: array (nullable = true)
| |-- element: array (containsNull = true)
| | |-- element: string (containsNull = true)
|-- person: string (nullable = true)
create UDF for our requirements
scala> def arrayConcat(array:Seq[Seq[String]], str: String) = array.map(_.map(str + _))
arrayConcat: (array: Seq[Seq[String]], str: String)Seq[Seq[String]]
scala> val arrayConcatUDF = udf(arrayConcat _)
arrayConcatUDF: org.apache.spark.sql.expressions.UserDefinedFunction = UserDefinedFunction(<function2>,ArrayType(ArrayType(StringType,true),true),Some(List(ArrayType(ArrayType(StringType,true),true), StringType)))
Applying the udf
scala> data.withColumn("dasd", arrayConcatUDF($"people", lit("Mr."))).show(false)
+--------------------------+------+-----------------------------------+
|people |person|dasd |
+--------------------------+------+-----------------------------------+
|[WrappedArray(ja, ji, he)]|person|[WrappedArray(Mr.ja, Mr.ji, Mr.he)]|
+--------------------------+------+-----------------------------------+
You may need to tweak a bit(I think any tweak is hardly required) but this contains the most of it to solve your problem
Upvotes: 0