CODEWITHSUNDEEP
pythonpython-3.xalgorithm
PlainText
PlainText

Reputation: 31

Extracting data to put in a variable from a list sequence

I'm trying to find a way to store in a variable of all the numbers from the players within allPlayers

I have been recommended to use the for loop which works but when you go to use it globally it only shows the last number not all of them. Preferably I would like it to be all within one line putting it into a variable but whatever is the simplest. 

player1 = ['David.G', '1204', '4th Catogory']
player2 = ['John.D', '1000', 'Unranked']
player3 = ['Barry.M', '1932', '1st Catogory']
player4 = ['Steven.H', '1844', '1st Catogory']
allPlayers = [player1, player2, player3, player4]

for player in allPlayers:
    fideRankings = player[1]
    global fideRankings

print("")
print(fideRankings)

Result is: 1204 1000 1932 1844

1844

I was looking for it to print the same four numbers outside the for loop.

Upvotes: 3

Views: 52

Answers (4)

Umesh Jadhav
Umesh Jadhav

Reputation: 327

player1 = ['David.G','1204','4th Catogory']
player2 = ['John.D','1000','Unranked']
player3 = ['Barry.M','1932','1st Catogory']
player4 = ['Steven.H','1844','1st Catogory']
allPlayers = [player1,player2,player3,player4]

for i in allPlayers:
    print(i[1],end=" ")

if you just want to print it outside of for loop:

player1 = ['David.G','1204','4th Catogory']
player2 = ['John.D','1000','Unranked']
player3 = ['Barry.M','1932','1st Catogory']
player4 = ['Steven.H','1844','1st Catogory']
allPlayers = [player1,player2,player3,player4]

string = ""
for i in allPlayers:
    string = string + " " + str(i[1])

print(string)

you can always use string.split(" ") to get those numbers in list if you need to use those numbers in future.

Upvotes: 1

Jithin P James
Jithin P James

Reputation: 762

Using list comprehension

player1 = ['David.G','1204','4th Catogory']
player2 = ['John.D','1000','Unranked']
player3 = ['Barry.M','1932','1st Catogory']
player4 = ['Steven.H','1844','1st Catogory']
allPlayers = [player1,player2,player3,player4]
print(" ".join([player[1] for player in allPlayers]))

result will be

1204 1000 1932 1844

or use as below if you need each player details in new lines

print("\n".join([player[1] for player in allPlayers]))

Result will be as below

1204 1000 1932 1844

Upvotes: 0

Mahir Islam
Mahir Islam

Reputation: 1972

You can use an empty list to append the numbers then print it out all together. Like this:

player1 = ['David.G','1204','4th Catogory']
player2 = ['John.D','1000','Unranked']
player3 = ['Barry.M','1932','1st Catogory']
player4 = ['Steven.H','1844','1st Catogory']
allPlayers = [player1,player2,player3,player4]
empty_list = []
for player in allPlayers:
    fideRankings = player[1]
    empty_list.append(fideRankings)
print(empty_list)

Hope it helps :)

Upvotes: 0

rassar
rassar

Reputation: 5660

Try:

>>> print([i[1] for i in allPlayers])
['1204', '1000', '1932', '1844']

This uses a list comprehension. It is equivalent to:

>>> ns = []
>>> for i in allPlayers:
... ns.append(i[1])

>>> ns
['1204', '1000', '1932', '1844']

Upvotes: 0

Related Questions