CODEWITHSUNDEEP
graphgremlintinkerpop3amazon-neptune
mmr25
mmr25

Reputation: 93

Gremlin get vertices where there exists a bidirectional edge connecting them

Mine is a simple social network scenario people make friends and post pictures and those pictures should be visible to people only if there exists a 2 way relation ship between them

g.addV("user").property("name","X").as('x').
  addV("user").property("name","Y").as('y').
  addV("post").property("name","p1").as('p1').
  addE("posts").from("x").to("p1").
  addE("friend").from("x").to("y").iterate()

right now there exists an only one-way relationship between X and Y. Y should only see the posts of X only if there exists bidirectional relations ship i.e

g.addE("friend").from(V().has("name","Y")).to(V().has("name","X")).iterate()

now there is both way edge of the same type between X and Y so both can view each other posts.

my code to get posts of all friends of Y but not working

g.V("name","Y").both("friend").out("posts").toList().next();

Upvotes: 1

Views: 429

Answers (1)

stephen mallette
stephen mallette

Reputation: 46206

One of the more direct way to write this is with:

g.V().has("name","Y").as('y').
  out('friend').
  where(__.in('friend').as('y')).
  out('posts').values('name')

So, find "Y" and label that step as "y", then traverse to friends, filter out any "friend" vertices who don't match back to "y" using where() then for those matches get the posts.

gremlin> g.addV("user").property("name","X").as('x').
......1>   addV("user").property("name","Y").as('y').
......2>   addV("post").property("name","p1").as('p1').
......3>   addE("posts").from("x").to("p1").
......4>   addE("friend").from("x").to("y").iterate()
gremlin> g.V().has("name","Y").as('y').
......1>   out('friend').
......2>   where(__.in('friend').as('y')).
......3>   out('posts').values('name')
gremlin> g.addE("friend").from(V().has("name","Y")).to(V().has("name","X")).iterate()
gremlin> g.V().has("name","Y").as('y').
......1>   out('friend').
......2>   where(__.in('friend').as('y')).
......3>   out('posts').values('name')
==>p1

Upvotes: 1

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