CODEWITHSUNDEEP
pythonif-statement
Nacka
Nacka

Reputation: 5

Why is the else statement not executed?

import random

words = ["Rock", "Paper", "Scissors"]

wins, loss = 0, 0

while True:

    word = random.choice(words)

    ur_word = input("Rock, Paper, Scissors..: ")

    print("\nComputer: {0}\nYou: {1}\n".format(word, ur_word))

    if word == ur_word:
        print("Tie!")
        continue
    elif ur_word == 'q':
        break
    elif word == 'Rock':
        if ur_word == 'Paper':
            print("You won!")
            wins += 1
        elif ur_word == 'Scissors':
            print("You lost!")
            loss += 1
    elif word == 'Paper':
        if ur_word == 'Rock':
            print("You lost")
            loss += 1
        elif ur_word == 'Scissors':
            print("You won!")
            wins += 1
    elif word == 'Scissors':
        if ur_word == 'Rock':
            print("You won!")
            wins += 1
        elif ur_word == 'Paper':
            print("You lost!")
            loss += 1
    else:                                        <<<<---------///----------HERE------------///----
        print("Please enter a valid input.")


    if wins == 3:
        print("\n\tYou won the entire game of three rounds!")
        break
    elif loss == 3:
        print("\n\tYou lost the entire game of three rounds!")
        break

**Now, my question is: why does the selected else statement not execute when I enter an arbitrary value like "74n9wndwekf"?

A guy told me that you cannot execute if and elif statements after an else statement, and also that you cannot execute your code after a break statement. I don't understand what he meant and I don't know whether this information is of any value to you.**

Upvotes: 0

Views: 630

Answers (2)

Anis R.
Anis R.

Reputation: 6902

In your if statement, you are checking the following:

  • if the computer's random choice is "Rock", do this..,
  • else if it is "Papers", do that..,
  • else if it is "Scissors", do that..,
  • else print invalid input.

The problem here is that the computer's random choice will always be either "Rock", or "Paper", or "Scissors", so one of the first three if/elif conditions will be met, therefore your else block will never be reached.

Try designing your if statements to check for the user input first instead of the computer's choice.

Upvotes: 0

Samwise
Samwise

Reputation: 71424

The else never happens because one of your elifs will always be true. word will always be one of Rock, Paper, or Scissors so you'll never hit that else.

A simple fix would be to restructure that chain of if...elif to check ur_word first.

Another way to go would be to validate the input before you do anything else, e.g.:

ur_word = input("Rock, Paper, Scissors..: ")
if ur_word not in {'Rock', 'Paper', 'Scissors', 'q'}:
    print("Please enter a valid input.")
    continue

Upvotes: 3

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