CODEWITHSUNDEEP
javascriptreactjsor-condition
CraZyDroiD
CraZyDroiD

Reputation: 7105

reactjs OR condition breaks in the second comparison

I'm trying to add different Id to a component based on a certain value.

My approach is like below

id={activePage === ('dashboard' || 'evc_detail')? 'bg_gradient':'bg_normal'}

In this scenario if the activePage is equal to dashboard the correct id is added but it does not register if activePage is equal to evc_detail. Is the way i'm using this condition wrong and how can i solve this?

Upvotes: 0

Views: 38

Answers (1)

Ori Drori
Ori Drori

Reputation: 191976

If you want to multiple comparisons you'll need to state them manually:

(activePage === 'dashboard' || activePage === 'evc_detail') ? 'bg_gradient' : 'bg_normal'

Another option is create an array of items (or a Set), and use Array.includes() (or Set.has) to check if an item is in the group:

const gradientPages = ['dashboard', 'activePage']

gradientPages.includes(activePage) ? 'bg_gradient' : 'bg_normal'

Your original expression activePage === ('dashboard' || 'evc_detail')? 'bg_gradient':'bg_normal' doesn't work if the activePage is not 'dashbarod' because of the way it's evaluated:

  1. 'dashboard' || 'evc_detail' is evaluated, since 'dashboard' is a truthy expression, the result is always dashboard.
  2. 'dashboard' is compared with activePage. If activePage is 'dashboard' the result is true, if not it's false.

Upvotes: 5

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