Reputation: 59345
I am looking for a way to reduce redundancy in my typescript typing. I am creating a specific type of class where:
Here's a working example of a class:
interface Wood {}
interface Chair {}
interface DiningRoom {}
interface LivingRoom {}
interface Nail {}
class House {
constructor () {
}
wood (i: {tree: string}): Wood {
return {}
}
nails (i: {nails: number}): Nail[] {
return [{}]
}
chair (i: {wood: Wood, nails: Nail[]}
& Parameters<House['wood']>[0]
& Parameters<House['nails']>[0]
): Chair {
return {}
}
diningRoom (i: {chair: Chair } & Parameters<House['chair']>[0]): DiningRoom {
return {}
}
livingRoom (i: {chair: Chair } & Parameters<House['chair']>[0]): LivingRoom {
return {}
}
}
I am looking for either a abstract class or generic type that would make it less redundant to write & Parameters<House['wood']>[0]
. Ideally an abstract class that would be able to see i: {chair: Chair}
as the parameter and know to add & Parameters<House['chair']>[0]
Upvotes: 0
Views: 26
Reputation: 327624
I am not sure if I understand what you're doing, and I have no idea if it's possible to do anything with inheritance that would make it possible to have subclass method parameters intersect with things automatically. As far as I can tell, the generic type corresponding to your parameters looks something like this:
type AllKeys<T> = T extends any ? keyof T : never;
type MakeParam<H extends Record<K, (x: any) => any>, K extends keyof any> =
{ [Q in K]: Parameters<H[Q]>[0] }[K] extends infer L ?
{ [Q in AllKeys<L>]: Extract<L, Record<Q, any>>[Q] } extends infer M ?
{ [P in K | keyof M]:
(P extends keyof M ? M[P] : unknown) &
(P extends K ? ReturnType<H[P]> : unknown)
} : never : never;
You use it like this:
type Test = MakeParam<House, "wood">;
/* type Test = {
wood: Wood;
tree: string;
} */
or for multiple keys, as a union like this:
type Test2 = MakeParam<House, "wood" | "nails">;
/* type Test2 = {
wood: Wood;
nails: number & Nail[];
tree: string;
} */
Notice that number & Nail[]
. That's weird and useless, but is exactly what your current code requires, so there you go. Presumably the object you pass into the nails()
method should not have a key named nails
. Duplicates will be intersected; use at your own risk.
Then you can refactor your House
definition like this:
class House {
constructor() {
}
wood(i: { tree: string }): Wood {
return {}
}
nails(i: { nails: number }): Nail[] {
return [{}]
}
chair(i: MakeParam<House, "wood" | "nails">): Chair {
return {}
}
diningRoom(i: MakeParam<House, "chair">): DiningRoom {
return {}
}
livingRoom(i: MakeParam<House, "chair">): LivingRoom {
return {}
}
}
And it works the same as your given code, I think.
I suppose you want an explanation for MakeParam<H, K>
. That could get really wordy, so I'm just going to give a sketch:
{ [Q in K]: Parameters<H[Q]>[0] }[K] extends infer L ? ... : never
This defines a type L
which is the union of all the parameters for the methods named in the K
union. When H
is House
and K
is "wood" | "nails"
, you get { tree: string } | { nails: number }
.
{ [Q in AllKeys<L>]: Extract<L, Record<Q, any>>[Q] } extends infer M ? ... : never
This defines a type M
which takes L
and turns the union into an "intersection" by extracting all the properties from all union pieces. When H
is House
and K
is "wood" | "nails"
, you get { tree: string, nails: number }
.
{ [P in K | keyof M]: (P extends keyof M ? M[P] : unknown) & (P extends K ? ReturnType<H[P]> : unknown) }
This makes a new object with all the properties from M
, and also adds properties with names in K
and types as the return type of the methods named by K
. Generally each property name should only appear in either K
or keyof M
, and if I knew that for sure I'd have done something like M[P] | ReturnType<H[P]>
(with some keyof
checks to make that compiler), but your nails
definition gave me pause and I had to make sure it behaved the same as your current thing, with the fun number & Nail[]
type coming out.
Okay, hope that helps. Good luck!
Upvotes: 1