CODEWITHSUNDEEP
htmlxslt
Ian R. O'Brien
Ian R. O'Brien

Reputation: 6920

Replace HTML Quotes with Plain Text in XSLT

We are using XSLT to translate a RIXML file to XML. Our RIXML contains the following text:

<Title><![CDATA[Looking into the future: Reiterate &#8216;Buy&#8217;]]></Title>

8216 is a left quote and 8217 is a right quote.

How would I replace these HTML codes with their plain text representation, or more simply, just a single quote? This is XSLT version 1.0.

Upvotes: 0

Views: 688

Answers (2)

Ian R. O&#39;Brien
Ian R. O&#39;Brien

Reputation: 6920

I came upon this function which worked well for me. I call it to replace all the characters I need to:

<xsl:template name="string-replace-all">
  <xsl:param name="text" />
  <xsl:param name="replace" />
  <xsl:param name="by" />
  <xsl:choose>
    <xsl:when test="contains($text, $replace)">
      <xsl:value-of select="substring-before($text,$replace)" />
      <xsl:value-of select="$by" />
      <xsl:call-template name="string-replace-all">
        <xsl:with-param name="text"
        select="substring-after($text,$replace)" />
        <xsl:with-param name="replace" select="$replace" />
        <xsl:with-param name="by" select="$by" />
      </xsl:call-template>
    </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="$text" />
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

Upvotes: 0

Dimitre Novatchev
Dimitre Novatchev

Reputation: 243449

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:variable name="vQ2">""</xsl:variable>

 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="text()">
  <xsl:value-of select=
   "translate(.,'&#8216;&#8217;',$vQ2)"/>
 </xsl:template>
</xsl:stylesheet>

Upvotes: 1

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