CODEWITHSUNDEEP
python
Emmitt Scheffler
Emmitt Scheffler

Reputation: 13

Input variable runs code after third attempt

I'm creating a test 'text adventure' game, and code is run based on the input() text, but when I try out the code and type in text for the input variable it doesn't run until I have tried a couple of times.

I've tried moving the location of the input() but it does the same thing.

def Inputs():
   while True:
    global Hour
    global Wait
    if input() == 'search' and Wait == False:
        for x in range(1):
          print('You got +',random.randint(0,5), 'food and +', random.randint(0,5), 'water')
        Hour = Hour + 1
        Wait = True
        t.start

    if input() == 'search' and Wait == True:
          print('You decide to wait before looking again.')


    if input() == 'search' and Wait == True:
      print('You decide to wait before looking again.')


    if input() == 'light' and Day == True:
      print('You light a fire.')      

    if input() == 'light' and Day == False:
      print('You cannot light a fire, it\'s day.')


    if input() == 'info':
      print(Info())


    if input() == 'craft':
      print('Test Text (Finish)')


    if input() == 'help':
      print(Instructions)

It should display 'You light a fire.'

Upvotes: 1

Views: 36

Answers (1)

Paul
Paul

Reputation: 333

Each time you call input() == XXX the interpreter ask for a new input so the loop takes 8 inputs before looping back.

You should call input once and store result in a variable.

Upvotes: 2

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