CODEWITHSUNDEEP
javamathintervalsdivide
user12332662
user12332662

Reputation:

How can I divide an interval [start,end] into n points of equal distance?

I have an interval from start to end where start and end are type double. I want to divide the interval into n points, where each two neighboring points are the same distance apart. For example:

// Given closed interval [-3.14,3.14]:
start = -3.14
end = 3.14
n = 3

// The 3 points would be:
-3.14, 0.0, 3.14

// Where the distance between each two neighboring points is 3.14

Or:

// Given left-closed, right-open interval [0,1):
start = 0
end = 1
n = 4

// The 4 points would be:
0.0, 0.25, 0.5, 0.75

// Where the distance between each two neighboring points is .25

I'm having trouble with this, appreciate any advice

Upvotes: 0

Views: 1510

Answers (1)

luk2302
luk2302

Reputation: 57214

According to the logic you have shown so far the the interval sizes are:

  • closed: (end - start) / (n - 1)
  • open one side: (end - start) / n
  • open both sides: (end - start) / (n + 1)

The initial left point is:

  • closed on the left: start
  • open on the left: start + interval.

All other points just add a interval on top

Upvotes: 2

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