CODEWITHSUNDEEP
python-3.xlistprinting
LEDIK
LEDIK

Reputation: 63

How to print list?

So i'm writing a code, listing square numbers lower than n. I want the output to be a list. like so: [1, 4, 9, 16] etc.

n=int(input("input number: "))
counter = 1
while counter * counter < n:
   for counter in range(1,n):
      a = counter*counter
      print (a)
   if a < n:
      break

I would be very grateful if I can get some help.

Upvotes: 1

Views: 31

Answers (1)

Chris Doyle
Chris Doyle

Reputation: 12199

you can remove the need for the while loop and utilise pythons range function to generate your numbers up to n and use a for loop to iterate over them. you also need to initalise a list to store them in before the loop starts. and then each iteration of the loop append the square number to the list.

n=int(input("input number: "))
squares = []
for num in range(1, n):
    squares.append(num * num)
print(squares)

OUTPUT for n=10

[1, 4, 9, 16, 25, 36, 49, 64, 81]

Although this can be simpfied using pythons list comprehension style as 

n=int(input("input number: "))
squares = [num * num for num in range(1, n)]
print(squares)

OUTPUT for n=10

[1, 4, 9, 16, 25, 36, 49, 64, 81]

UPDATE based on comment from B. Go

user B. Go pointed out that my answer is printing all the results of squaring number up to the value of N. But the question was actually print all the square numbers less than N. Below code to print squares less than N

n=int(input("input number: "))
squares = []
for num in range(1, n):
    result = num * num
    if result >= n:
        break
    squares.append(num * num)
print(squares)

OUTPUT N=50

[1, 4, 9, 16, 25, 36, 49]

Upvotes: 2

Related Questions