Reputation: 196
I need a little bit of help with using pointers in C++. Sorry to seem beginner but I really can't quite understand them. I have read the tutorial on pointers on the cplusplus.com website, so please don't suggest that.
I basically have a variable which holds the name of another variable, and I wish to access that variable through the holder one. I believe I need to use pointers, correct me if I'm wrong though.
E.g.
int a;
string b;
a = 10;
b = "a";
I need to access the variable "a" through the contents of variable "b".
Just to put this into better perspective, this is how I am using it:
int a;
a = 20;
void getVar(string name) {
cout << name;
}
getVar("a");
But as you can see, on the fifth line, that will just cout the value of name, in this case "a", but I want it to cout the value of the variable which name contains, so I want it to output "20".
Any help here would be much appreciated.
Upvotes: 0
Views: 128
Reputation: 57688
If you need to associate a name with a value, consider associative arrays otherwise known as dictionaries and maps. The Standard Template Library has std::map
that you can use to associate text with a value:
#include <map>
#include <string>
std::map<std::string, int> my_map;
my_map["A"] = 20;
cout << my_map["A"] << endl;
Upvotes: 4
Reputation: 21
quick fix for outputting integers only:
int a; a = 20;
void getVar(int name) { cout << name; }
getVar(a);
If you need the function to work for any type of variable, maybe think about some template function.
Edit: Here is the code for the template program:
#include <iostream>
#include <string>
using namespace std;
template <class T>
void getVar(T name){
cout<<name<<endl;
}
int main()
{
string x="hee";
int y=10;
getVar(x);//outputs hee
getVar(y);//outputs 10
return 0;
}
Upvotes: 0
Reputation: 14705
What you are trying to achieve is not possible in a compiled language (not considering reflection). You might accomplish something similar using a map data structure.
theMap["a"] = 20;
and a corresponding
void getVar(string key){
cout << theMap[key];
}
that can be called with
getVar("a");
Note that in this extremely simple sample theMap has to be in scope for the function, like in a class or a namespace.
If you use pointers you are just using a level of indirection not at all suited for your example. See Chads answer for instance.
Upvotes: 2
Reputation: 61361
What you're asking for is called "reflection" or "introspection" - the ability to use design-time names for your program's objects (classes, variables, functions, etc) in run time. C++ does not support that out of the box - the design-time names are stripped upon compilation.
There are some libraries that provide that capability in C++; but there are also languages where reflection is is part of the language. Python or JavaScript, for example.
Upvotes: 1
Reputation: 7672
Your code does not use pointers. you're trying to convert a string into an identifier and print it's result, I don't know whether that's possible or not. If you intended using pointer your code should've looked like this:
int a = 20;
int* b = &a;
cout << *b;
Upvotes: 0
Reputation: 79185
Maybe this could suit you:
int a = 5;
class b {
public:
b(int &x) { ref_ = x; }
int operator()(void) { return ref_; }
private:
int &ref_;
}
b my_b(a);
my_b() /* -> 5 */;
Upvotes: 0
Reputation: 19609
What you are thinking of is called (Reflection) which C++ does not support. You can however use pointers to access what is in a variable it points to:
int a = 5; //int variable that stores 5
int *b = &a; //int pointer that stores address of a
(*b) = 10; //stores 10 into address that b points to (a)
cout << a; //prints 10
Upvotes: 2
Reputation: 17732
Theres no real way for you to access variables by name like that unless you create some kind of container class that has a name member that you look up by. I'm not sure what this has to do with pointers though.
Upvotes: 1