Reputation: 427
Please see the code that I wrote based on a school example.
public class Test {
public static void main(String [] args)
{
int number = 0;
int [] array = new int[number+1];
array[number] = 0;
methodName(number, array);
}
public static void methodName(int n, int[] b )
{
if (n == 0)
{
System.out.println(" b is : " + b);
return;
}
else
{
b[n-1] = 0;
methodName(n-1, b);
b[n-1] = 1;
methodName(n-1, b);
}
}
}
I am trying to calculate the best and worst case time complexity of this code. As far as I understand the best case would be O(1). And I'm having a difficulty determining the worst case. There are four basic operations in the else loop. I know that this is a progressively growing function and I have a feeling it is close to being O(!n).
Thank you for your time.
Upvotes: 0
Views: 150
Reputation: 106
IF methodName is not getting called from anywhere else than main, then it would always be O(1)
Upvotes: 1