CODEWITHSUNDEEP
pythonpython-3.xlist
Bhavin Thakar
Bhavin Thakar

Reputation: 98

how to check if an element equals to specific index of multidimensional list

I have two multidimensional list I have to check if the element is in the multidimensional list My code is:

import tkinter as tk
from tkinter import filedialog
import numpy as np
import os
root= tk.Tk()
root.withdraw()
filepath =filedialog.askopenfilename(filetypes = (("trace files","*.trace"),("out files",".out")))
file=open(filepath)
file_path = file.name
ext= os.path.splitext(file_path)
readData=file.readlines()
list1=[]
list2=[]
pht=[[1,0]]
goodPred=0
badPred=0
count=0

for read in readData:
    split= read.split(' ')
    addr =split[0]
    action= split[1]
    list1.append([addr,action.strip()])


    # if(len(pht)>500):
    #     del pht[0]
for i in range(len(list1)):


    if list1[i][0] in pht ##how to check from index 1 of pht for eg:pht[##what to mention here##][1]##:

        list2_index = list2.index(list1[i][0])
        print(list2_index)
    else:
        # print(list1[i][0])
        list2.append(list1[i][0])

My list1 is as follows:

[['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T'], ['3086703274', 'T']]

My Pht is as follows for eg:

[['1','3086703274'], ['1','3086703274'], ['1','3086703274',]]

How can I use pht of second element of every sublist in the list and compare it with list1[i][0]

Upvotes: 1

Views: 55

Answers (1)

Bruno Vermeulen
Bruno Vermeulen

Reputation: 3455

if list1[i][0] in [val[1] for val in pht]:

If pht is a fixed list then of course you are not going to calculate it in each loop but put [val[1] for val in pht] in a new list like pht_keys, thus:

pht_keys = [val[1] for val in pht]
for index, element in enumerate(list1):
    if element[0] in pht_keys:
        list_2_index = list2.index(index)
...

I discourage the use of

for i in range(len(list1)):
   print(f'element index {i} is {list1[i]}')

Do it the pythonic way with enumerate if you need the index

for index, element in enumerate(list1):
   print(f'element index {index} is {element}')

Upvotes: 1

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