Reputation: 622
I'm looking for a way to change the variables defined inside a function after defining the function.
For example
def GetNthPower(x) :
n = None
return x**n
my_numbers_list = [11,23,45,56,78,98]
# now if I feel like I need the 4th power of some numbers in the list
GetNthPower.n = 4
for x in my_numbers_list :
print GetNthPower(x)
# If I want 7th power then
GetNthPower.n = 7
This obviously will not work, is there any way to do this?
N.B: I know we can achieve this by setting 'n' as an argument of the function, but I want to do it this way for a particular reason.
I want my function to have only one argument (for using the function in multiprocessing.Pool.map()
).
Upvotes: 1
Views: 104
Reputation: 13106
Alternatively, you could use functools.partial
to bind a keyword argument to a function
from functools import partial
def get_nth_power(x, n):
return x ** n
get_third = partial(get_nth_power, n=3)
get_third(4)
64
x = 4
# in a loop
for pow in [2, 4, 6, 8]:
f = partial(get_nth_power, n=pow)
f(x)
Upvotes: 2
Reputation: 531305
Don't use one function; create a function that makes your function, using a closure.
def nth_power_maker(n):
def _(x):
return x ** n
return _
my_numbers_list = [11,23,45,56,78,98]
# now if I feel like I need the 4th power of some numbers in the list
get_4th_power = nth_power_maker(4)
for x in my_numbers_list:
print(get_4th_power(x))
get_7th_power = nth_power_maker(7)
Upvotes: 2
Reputation: 4943
You can define static variables inside functions, almost like you did:
def GetNthPower(x) :
return x ** GetNthPower.n
GetNthPower.n = 3
print(GetNthPower(2)) #8
Make sure to initialize correctly your GetNthPower.n
before first use though.
If you're worried about initialization, you could go for this version which uses a default value 1
:
def GetNthPower(x) :
return x ** (GetNthPower.n if hasattr(GetNthPower, "n") else 1)
I think it would still be better for you to write a function that takes two arguments, or use the predefined **
operator.
Upvotes: 3