Reputation: 7733
I have a dataframe like as shown below
df = pd.DataFrame({
'subject_id':[1,1,1,1,1,1,1,2,2,2,2,2],
'time_1' :['2173-04-03 12:35:00','2173-04-03 12:50:00','2173-04-05 12:59:00','2173-05-04 13:14:00','2173-05-05 13:37:00','2173-07-03 13:39:00','2173-07-04 11:30:00','2173-04-04 16:00:00','2173-04-09 22:00:00','2173-04-11 04:00:00','2173- 04-13 04:30:00','2173-04-14 08:00:00'],
'val' :[5,5,5,5,1,6,5,5,8,3,4,6]})
df['time_1'] = pd.to_datetime(df['time_1'])
df['day'] = df['time_1'].dt.day
df['month'] = df['time_1'].dt.month
What I would like to do is drop records/subjects who doesn't have more than 4 or more
unique days
If you see my sample dataframe, you can see that subject_id = 1
has only 3 unique dates which is 3,4 and 5
so I would like to drop subject_id = 1
completely. But if you see subject_id = 2
he has more than 4 unique dates like 4,9,11,13,14
. Please note that date values has timestamp, hence I extract the day from each datetime field and check for unique records.
This is what I tried
df.groupby(['subject_id','day']).transform('size')>4 # doesn't work
df[df.groupby(['subject_id','day'])['subject_id'].transform('size')>=4] # doesn't produce expected output
I expect my output to be like this
Upvotes: 2
Views: 37
Reputation: 863166
Change your function from size
to DataFrameGroupBy.nunique
, grouping only by the subject_id
column:
df = df[df.groupby('subject_id')['day'].transform('nunique')>=4]
Or alternatively you can use filtration, but this should be slower if you're using a larger dataframe or many unique groups:
df = df.groupby('subject_id').filter(lambda x: x['day'].nunique()>=4)
print (df)
subject_id time_1 val day month
7 2 2173-04-04 16:00:00 5 4 4
8 2 2173-04-09 22:00:00 8 9 4
9 2 2173-04-11 04:00:00 3 11 4
10 2 2173-04-13 04:30:00 4 13 4
11 2 2173-04-14 08:00:00 6 14 4
Upvotes: 3