Reputation: 1270
I'm am trying to make a regex expression that matches at most 7 groups.
((X:){1,6})((:Y){1,6})
X:X:X:X:X::Y:Y This should match
X:X:X:X:X:X::Y:Y This should not match.
https://regex101.com/r/zxfAB7/16
Is there any way to do this? I need the capture group $1 and $3
I am using C++17 regex.
Upvotes: 0
Views: 200
Reputation: 15265
Although there is already an accepted answer, I would like to show an ultra simple straightforward solution. Tested with C++17. And a complete running source code.
Since we are talking about max 7 groups, we can simply list them all up and 'or' them. This is maybe much text and a complex DFA. But it should work.
After we found the match, we define a vector and put all data/groups into it and show the desired result. This is really simple:
Please see:
#include <iostream>
#include <string>
#include <iterator>
#include <vector>
#include <regex>
std::vector<std::string> test{
"X::Y",
"X:X::Y",
"X:X::Y:Y",
"X:X:X::Y:Y",
"X::Y:Y:Y:Y:Y",
"X:X:X:X:X::Y:Y",
"X:X:X:X:X:X::Y:Y"
};
const std::regex re1{ R"((((X:){1,1}(:Y){1,6})|((X:){1,2}(:Y){1,5})|((X:){1,3}(:Y){1,4})|((X:){1,4}(:Y){1,3})|((X:){1,5}(:Y){1,2})|((X:){1,6}(:Y){1,1})))" };
const std::regex re2{ R"(((X:)|(:Y)))" };
int main() {
std::smatch sm;
// Go through all test strings
for (const std::string s : test) {
// Look for a match
if (std::regex_match(s, sm, re1)) {
// Show succes message
std::cout << "Match found for --> " << s << "\n";
// Get all data (groups) into a vector
std::vector<std::string> data{ std::sregex_token_iterator(s.begin(), s.end(),re2,1), std::sregex_token_iterator() };
// Show desired groups
if (data.size() >= 6) {
std::cout << "Group 1: '" << data[0] << "' Group 6: '" << data[5] << "'\n";
}
}
else {
std::cout << "**** NO match found for --> " << s << "\n";
}
}
return 0;
}
Upvotes: 0
Reputation: 163577
If a positive lookahead is supported, you might use a positive lookahead to assert not 8 repetitions of either X:
or :Y
.
To prevent an empty match you could use a positive lookahead to check if there is at least 1 match.
Then use 2 capturing groups where you repeat 0+ times either matching X:
in the first group a and 0+ times matching :Y
in the other group.
^(?=(?:X:|:Y))(?!(?:(?:X:|:Y)){8})((?:X:)*)((?::Y)*)$
^
Start of string(?=
Postive lookahead, assert what is on the right is
(?:X:|:Y)
Match either X:
or :Y
)
Close positive lookahead(?!
Negative lookahead, assert not 8 times matching either X:
or :Y
(?:(?:X:|:Y)){8}
)
close negative lookahead((?:X:)*)
Capture group 1 Match 0+ times X:
((?::Y)*)
Capture group 2 Match 0+ times :Y
$
End of stringUpvotes: 1
Reputation: 17565
As mentioned by Ulrich, just using regular expressions might not be the solution. I'd advise you the following:
Replace all X (occuring 1 to 6 times) by an empty string
Replace all Y (occuring 1 to 6 times) by an empty string
Use regex for determining if any X is still present
Use regex for determining if any Y is still present
In case all X
or Y
appear only 1 to 6 times, no X
or Y
will be found (return match
), else return no match
.
Upvotes: 0