CODEWITHSUNDEEP
bashshellunixsh
dilipyadav
dilipyadav

Reputation: 53

Splitting a String in unix

I am trying to split a string in unix shell script, but I am not able to figure out. Any help would be appreciated. Below is the example 

    olap4j-xmla-1.0.1.500,

    olap4j-xmla-1.2.0,

    olap4j-xmla-1.2.0.SNAPSHOT,

    olap4j-xmla-1.2.0.RELEASE

The above strings will be split so that the output will be stored in different variables like

  var1=olap4j-xmla    var2=1.0.1.500

  var1=olap4j-xmla    var2=1.2.0

  var1=olap4j-xmla    var2=1.2.0    var3=SNAPSHOT

  var1=olap4j-xmla    var2=1.2.0    var3=RELEASE

Upvotes: 1

Views: 78

Answers (2)

stephanmg
stephanmg

Reputation: 766

#!/bin/bash
while read LINE; do
  var1=$(cut -d '-' -f1,2 <<< "$LINE")
  tmp=$(cut -d '-' -f3 <<< "$LINE")
  var2=$(sed 's/\(.*\)\.[a-zA-Z]*$/\1/' <<< "$tmp")
  var3=$(sed -n 's/.*\.\([a-zA-Z]*$\)/\1/p' <<< "$tmp")
  echo -e "var1=$var1; var2=$var2; var3=$var3"
done < file.txt

Output:

  var1=olap4j-xmla; var2=1.0.1.500; var3=
  var1=olap4j-xmla; var2=1.2.0; var3=
  var1=olap4j-xmla; var2=1.2.0; var3=SNAPSHOT
  var1=olap4j-xmla; var2=1.2.0; var3=RELEASE

Upvotes: 0

anubhava
anubhava

Reputation: 785098

Using string substitutions:

s='olap4j-xmla-1.0.1.500'
read var1 var2 <<< "${s%-*} ${s##*-}"

Now check variables:

declare -p var1 var2
declare -- var1="olap4j-xmla"
declare -- var2="1.0.1.500"

Update:

Thanks to comment from pjh below I have realized that OP needs 3 variable for some cases instead of 2.

Looking at that I think following sed will work better:

sed -E 's/^(.+)-([0-9.]+)(\.([^0-9]+))?$/\1 \2 \4/' <<< "olap4j-xmla-1.2.0.SNAPSHOT"
olap4j-xmla 1.2.0 SNAPSHOT

sed -E 's/^(.+)-([0-9.]+)(\.([^0-9]+))?$/\1 \2 \4/' <<< "olap4j-xmla-1.2.0"
olap4j-xmla 1.2.0

Output of sed can be fed into read as shown in above examples.

Upvotes: 3

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