CODEWITHSUNDEEP
shellunix
shome
shome

Reputation: 1402

Rename files in a folder to one name

I have multiple .pdb files in different folders. How to loop in through entire directory naming all files to one particular name test.pdb?

Sample structure

file1 
 file1.pdb
 xyz.txt

file2
 file2.pdb 
 xyz.txt

file3
 file3.pdb
 xyz.txt

Desired output structure

file1
 test.pdb
 xyz.txt

file2
 test.pdb
 xyz.txt

file3
 test.pdb
 xyz.txt

The code I am using at the moment :

for d in */ ; do
    mv *.pdb test.pdb
done

But it is not working.

Upvotes: 0

Views: 51

Answers (3)

dash-o
dash-o

Reputation: 14432

Alternative solution, iterating of the pdf files, instead of the folder names.

It's not clear if other pdb file, whose names does not match the folder name should be affected too. The code test for this condition. It can be removed if not needed.

for file in */*.pdb ; do
    d=$(dirname $file)
    b=$(basename $file .pdb)
    [ "$d" = "$b" ] && mv "$d/$b.pdb" "$d/test.pdb"
done

Upvotes: 0

slashpai
slashpai

Reputation: 1169

Try this

for d in */; do
  if [ -f $d/*.pdb ] ;then
    mv $d/*.pdb $d/test.pdb
  fi
done

Upvotes: 0

tripleee
tripleee

Reputation: 189327

You need to include the directory name. Just *.pdb will always expand to the files matching the wildcard in the current directory.

for d in ./*/ ; do
    mv "$d/"*.pdb "$d/"test.pdb
done

I added the ./ before the wildcard as a precaution too. It helps avoid problems if a file name starts with a dash, which would then get interpreted as an option to mv without the leading dash.

Many mv implementations will refuse to move multiple files to the same destination name, so this will probably only work if the wildcard expands to exactly one file in each directory. (Zero matches will work, but emit a noisy warning.)

Upvotes: 1

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