CODEWITHSUNDEEP
c#jsonmappingautomapper
Alexander Groshev
Alexander Groshev

Reputation: 168

Mapping json complex object to plain object

What I am doing is converting JSON that I get from YAHOO weather to my YahooWeatherModel class.

My json object after deserialisation (I use json.net) looks like this:

public class WeatherObject
{
    public Location location { get; set; }
    public List<Forecasts> forecasts { get; set; }
}

public class Location
{
    public string country { get; set; }
    public string city { get; set; }
}

public class Forecasts
{
    public string Day { get; set; }
    public string Date { get; set; }
    public string Low { get; set; }
    public string High { get; set; }
    public int Text { get; set; }
    public int Code { get; set; }
}

what I need is to convert this object to something like this:

public class YahooWeatherModel
{
    public string Country { get; set; }
    public string City { get; set; }
    public string Day { get; set; }
    public DateTime Date { get; set; }
    public int Low { get; set; }
    public int High { get; set; }
    public int Text { get; set; }
    public int Code { get; set; }
}

I use Automapper for mapping. I understand how to create map for location class part in my WeatherObject:

var configuration = new MapperConfiguration(cfg => cfg
    .CreateMap<WeatherObject, YahooWeatherModel>()
    .ForMember(dest => dest.Country, opt => opt.MapFrom(map => map.location.country))
    .ForMember(dest => dest.City, opt => opt.MapFrom(map => map.location.city))

But how can I convert List to plain data without list? For example in location I have country=latvia, city=riga and in forecast I have 7 items for each week day with other weather data.

What I want to get is list of YahooWeatherModel with 7 elements with country, city, day, low, high... etc info

Upvotes: 0

Views: 227

Answers (1)

Nick Henry
Nick Henry

Reputation: 109

You can do this using LINQ:

public void Convert(WeatherObject weatherObject)
{
    IEnumerable<YahooWeatherModel> models = from forecast in weatherObject.forecasts
        select new YahooWeatherModel
        {
            Country = weatherObject.location.country,
            City = weatherObject.location.city,
            Code = forecast.Code,
            Date = System.Convert.ToDateTime(forecast.Date),
            Day = forecast.Day,
            High = System.Convert.ToInt32(forecast.High),
            Low = System.Convert.ToInt32(forecast.Low),
            Text = forecast.Text
        };
}

Upvotes: 1

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