CODEWITHSUNDEEP
c#.net
dev12012
dev12012

Reputation: 33

string concatenation convert to int and perform calculation

Say I have the following 

 string = "make {0}{1} in {2} to produce {0}{1} in {2} minutes";

This pulls the correct values for {0} {1} {2} which works fine, for the second {0} {1} I want to divide the value for {0} by 2.

What is the best way to do this?

Upvotes: 0

Views: 71

Answers (3)

nzrytmn
nzrytmn

Reputation: 6961

It is string interpolation

Microsoft suggest to use "$" character to interpolate strings. This make code more readable and concise. A basic usage is like this :

 double speedOfLight = 299792.458;
 string message = $"The speed of light is {speedOfLight} km/s.";

In your case it should be :

string result = $"make {0/2}{1} in {2} to produce {0/2}{1} in {2} minutes";

The $ special character identifies a string literal as an interpolated string. An interpolated string is a string literal that might contain interpolation expressions. When an interpolated string is resolved to a result string, items with interpolation expressions are replaced by the string representations of the expression results. This feature is available starting with C# 6.

String interpolation provides a more readable and convenient syntax to create formatted strings than a string composite formatting feature.

Upvotes: 0

Tanveer Badar
Tanveer Badar

Reputation: 5512

You can use something like this.

string = $"make {var1}{var2} in {var3} to produce {var1/2}{var2} in {var3} minutes";

If that does not work due to language version restrictions, it can be done through string.Format() like this:

string = string.Format("make {0}{1} in {2} to produce {3}{1} in {2} minutes", var1, var2, var3, var1/2);

Upvotes: 1

CodeCaster
CodeCaster

Reputation: 151674

It's called a format string and not a calculation string.

So you'll have to do the calculation yourself, causing the positional arguments to increment in number (3 in this case):

string = string.Format("make {0}{1} in {2} to produce {3}{1} in {2} minutes", 
                       val0, val1, val2, val0 / 2);

Upvotes: 2

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