CODEWITHSUNDEEP
c#picturebox
Nulltiton
Nulltiton

Reputation: 25

How to change image in picturebox C#

I need to change the image by clicking on pictureBox, but when I click it again I can't return former picture

Here is my code:

private void PictureBox_Click(object sender, EventArgs e)
{
    if (pictureBox.Image == Properties.Resources.openeye)
        pictureBox.Image = Properties.Resources.closeeye;
    else
        pictureBox.Image = Properties.Resources.openeye;
}

How can I fix it?

Upvotes: 1

Views: 2480

Answers (4)

Sayed M. Idrees
Sayed M. Idrees

Reputation: 1408

You can use this.

    private void pictureBox1_Click(object sender, EventArgs e)
    {
        if (pictureBox1.Image!=null&& getSignatureLen( pictureBox1.Image) == getSignatureLen(Properties.Resources.openeye))
        {
            pictureBox1.Image = Properties.Resources.closeeye;
        }
        else
        {
            pictureBox1.Image = PProperties.Resources.openeye;
        }
    }

    public long  getSignatureLen(Image img)
    {
        using (System.IO.MemoryStream mStream = new System.IO.MemoryStream())
        {
            img.Save(mStream, img.RawFormat);
            return mStream.Length;
        }
    }

Upvotes: 0

n234
n234

Reputation: 249

Here's an example that demonstrates it with two images. One of an "x" another of an "o".

As you can see, the form has two instance variables x and o to store each of the Image objects. There is another flag field called isX which the ClickHandle event handler uses to check which image is currently displayed and switch to the other image, the event handler then toggles the isX field so the next click responds properly.

public void Main(string[] args)
{
    var f1 = new Form1(); // form instance that holds the PictureBox

    Task.Run(() => Application.Run(f1)); //I'm running this from LINQPad, but this would also work in a console application.
}

public class Form1 : Form // Derives from the Form class
{
    private bool isX; // private instance variable to indicate which image is diplayed
    private Image x; // private instance variable storing the x image
    private Image o; // private instance variable storing the o image

    // the picture box this form uses
    private PictureBox p;

    public Form1()
    {
        // load the images from wherever they are stored.
        // I do this at construction time to avoid doing disk IO when clicking
        x = Image.FromFile(@"C:\image\path\x.png");
        o = Image.FromFile(@"C:\image\path\o.png");

        // Initialize the picture box
        p = new PictureBox {
            Name = "p1",
            Size = new Size(100,100),
            Location = new Point(100,100),
            Image = o //Initialize with the o image
        };

        // register the click event handler
        p.Click += this.ClickHandle;

        // set the flag to false, since the o image is what we start with
        this.isX = false;

        // add PictureBox p to the form
        this.Controls.Add(p);
    }

    // handles the click action, registered to the PictureBox.Click event
    private void ClickHandle(object sender, EventArgs e)
    {
        // use the flag to check which image is shown, and display the other image
        if(this.isX) // this might work with your image == check, I didn't test it
        {
            p.Image = this.o;
        }
        else
        {
            p.Image = this.x;
        }
        // set the flag to the opposite of whatever the flag currently is
        this.isX = ! isX;
    }
}

o image

x image

Upvotes: 2

tobeypeters
tobeypeters

Reputation: 484

You can save the value in the un-used Tag property, of the PictureBox object.

pictureBox1.Tag = 1; //Set it to whatever

if (pictureBox1.Tag == "1") { } //Do your check

Upvotes: -1

Mateech
Mateech

Reputation: 1064

You can set value of picturebox image, but you cant get it that way.

You can set value of picturebox image, but you cant get it that way.

U can use global variable out of method and go this way.

    int i = 0;

    private void PictureBox1_Click(object sender, EventArgs e)
    {            
        if (i == 0)
        {
            pictureBox1.Image = Properties.Resources.close;
            i++;
        }                   
            else
        {
            pictureBox1.Image = Properties.Resources.open;
            i--;
        }                               
    }

Upvotes: 1

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