Reputation: 81
I'm trying to make a jquery code where you can show different images (1-3 different images) when you move the mouse around.
The images will be right beside the cursor, and they will only appear 1-3, not more than that. And each time the mouse moves, these images will change.
I currently have this as my html code,
<div class="mainbody">
<section class="container">
<div class="img_div">
</div>
</section>
</div>
And my jquery code looks like this:
let img_array = ['./img/awards_icon.png', './img/norinuri_icon.png'];
$("div.mainbody").mousemove(function(e) {
for(i=0; i<img_array.length; i++){
$('.img_div').append("<img src='" + img_array[i] +"'/>");
$('.img_div').fadeIn("5000");
$('.img_div').finish().fadeOut("5000");
$('.img_div').offset({
left: e.pageX,
top: e.pageY + 20
});
}
});
The 2 images that I have in my jquery array appears when the mouse moves, but instead of only having 2 images these images add continuously, without stopping. So each time I would move my mouse, the images would continue to add infinitely.
I will add more images in the jquery array for sure, but how should I have only two images added, and change these images as I move the mouse?
Upvotes: 2
Views: 248
Reputation: 99
I have created a working example for you. You can try it now:
<div class="mainbody">
<section class="container">
<div class="img_div">
hello
</div>
</section>
css
.mainbody {
border:1px solid red;
display:block;
height:1000px
}
jquery
let img_array = ['https://anotherjavaduke.files.wordpress.com/2018/08/avataaars-2.png',
'https://images2.minutemediacdn.com/image/upload/c_crop,h_1192,w_2121,x_0,y_111/f_auto,q_auto,w_1100/v1554921884/shape/mentalfloss/22461-istock-176984635.jpg'];
$("div.mainbody").on('mousemove', function(e) {
var i;
$('.img_div').html('')
for (i = 0; i < img_array.length; i++) {
console.log($('.img_div').has('img').length)
if ($('.img_div').has('img').length < img_array.length) {
$('.img_div').append("<img style='width:100px; height:100px' src='" + img_array[i] + "'/>");
$('.img_div').fadeIn("5000");
$('.img_div').finish().fadeOut("5000");
$('.img_div').offset({
left: e.pageX,
top: e.pageY + 20
});
}
}
});
Working example
[Codepen] https://codepen.io/prashen/pen/ZEEqJEo
Upvotes: 0
Reputation: 16261
Use background-image
var imageArr=["https://www.w3schools.com/css/paper.gif","https://www.w3schools.com/css/gradient_bg.png","https://www.w3schools.com/css/img_tree.png"];
var count=0;
$( ".mainbody" ).mouseover(function() {
$( ".img_div" ).css('background-image', 'url("' + imageArr[count] + '")');
if(count == imageArr.length-1)
count=0;
else
count++;
});
.mainbody{
width: 500px;
height: 500px;
border:1px solid red;
}
.img_div{
width: 200px;
height: 200px;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="mainbody">
<section class="container">
<div class="img_div">
</div>
</section>
</div>
USING mousemove
(to avoid the images to change so many times while mouse move I use timeout
)
var imageArr=["https://www.w3schools.com/css/paper.gif","https://www.w3schools.com/css/gradient_bg.png","https://www.w3schools.com/css/img_tree.png"];
var count=0;
var timeoutid = 0;
function setImage() {
$( ".img_div" ).css('background-image', 'url("' + imageArr[count] + '")');
if(count == imageArr.length-1)
count=0;
else
count++;
}
$(".mainbody").mousemove(function() {
clearTimeout(timeoutid);
timeoutid = setTimeout(setImage, 100);
});
.mainbody{
width: 500px;
height: 500px;
border:1px solid red;
}
.img_div{
width: 200px;
height: 200px;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="mainbody">
<section class="container">
<div class="img_div">
</div>
</section>
</div>
화이팅!
Upvotes: 1