CODEWITHSUNDEEP
pythonregex
John R Perry
John R Perry

Reputation: 4192

How to get every character in a string that comes before any integer?

If I had a string that looked like this:

hello my name is12345 blah blah things

and another one that looked like this:

slim shady4321 oooh la la

How would I grab only the characters that come before the integers?

Is the best way to loop through all of the characters in the string and check whether the character is an integer and then break from the loop?

Upvotes: 0

Views: 466

Answers (5)

user7548672
user7548672

Reputation:

No regex, no imports, just simple built in class.

s = 'hello my name is12345 blah blah things'
ss = 'slim shady4321 oooh la la'
w = ''
for c in ss:                                 # OR use the below
    if str(c).isalpha() or str(c).isspace(): # if not str(c).isdigit():
        w += c
    else:
        break;

print(w)

output:

hello my name is
slim shady

Upvotes: 0

Radoslaw Dubiel
Radoslaw Dubiel

Reputation: 122

I would go for simplicity:

s = "hello my name is12345 blah foo432423 blah things"

words = s.split(' ')

for word in words:
    if not word.isalpha():
        print(word.rstrip('0123456789'))

This splits your string into words and check every single one if it contains only letters. If not (what we are looking for), we take that word and remove trailing numbers. Gives you:

is
foo

Upvotes: 0

Anis R.
Anis R.

Reputation: 6922

You could use the following regex:

^\D*

Explanation:

^: Start symbol (make sure the match is from beginning of string) \D*:Sequence of characters that are non-digits.

(Assuming that in your examples you only want to retrieve hello my name is and slim shady).

Upvotes: 1

Ivor Denham-Dyson
Ivor Denham-Dyson

Reputation: 695

You could use positive look ahead. Match all non-digit characters before a digit.

\D*(?=\d)

Upvotes: 0

Ougaga
Ougaga

Reputation: 127

you can use regular expression to solve your problem (while using search pattern from user ctwheels)

import re

pattern = '\D+(?=\d)'

string1 = 'hello my name is12345 blah blah things'
string2 = 'slim shady4321 oooh la la'

match = re.search(pattern, string1)
match.group(0)

will return

'hello my name is'

Upvotes: 0

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