CODEWITHSUNDEEP
javaarraysstringif-statementreturn-type
MitchSibs
MitchSibs

Reputation: 1

how to return a word from a string

I apologize for the messy code, but these are two methods are ones we are supposed to use. I have to find the word end in a given string, if there is no end in the string return an empty string. ex (the, end said the author) output= the end

public class end {

    /**
    * find first apperance of the word end.
     * return the string up to word end
     * return empty string if the word end isn't there 
     */

    public static int endArray(String[] words) {
        int end = 0;
        for (int i = 0; i < words.length; i ++) {
            end ++;
            if (words[i] == "end") {
                end++;
            } else {
                end = -1;
            }
        }
    }

    public static String end(String[] words) {
        String end = "-1";
        for (int i = 0; i < words.length; i ++) {
            end+= words[i];
            if (words[i] == "end") {
                System.out.println(words[i-1]);
                end++;
            }

        }    
        return end;
    }
}

Upvotes: 0

Views: 327

Answers (2)

Madhubala
Madhubala

Reputation: 56

Try this code:

import java.util.*;
public class Main
{
    public  String getSortedGrades(String[] arg){
    String newStr = "";
    for(int i=0; i<arg.length; i++){
        if(arg[i]=="end"){
            newStr+=arg[i];
            return newStr;
        }else{
            newStr+=arg[i]+" ";
        }
    }
    return newStr.contains("end")?newStr: " " ;
}
    public static void main(String []args){
        System.out.println("Hello World");
        Main m =new Main();
        String[] input ={"the", "end", "said", "the", "author"}; 
       String s =  m.getSortedGrades(input);
       System.out.println(s);
    }
}

Upvotes: 0

Michel_T.
Michel_T.

Reputation: 2821

First of all, you should know, that it's incorrect to compare strings with == use the equals method instead: if ("end".equals(words[1])) { ...

I'd implement it like that:

public static String end(String[] words) {
    String allStrings = ""; // actually, it'd be better to use StringBuilder, but for your goal string concatination is enough
    for (int i = 0; i < words.length; i++) {
        if ("end".equals(words[i])) {
            return allStrings;
        }
        allStrings += words[i]; // maybe here we should add spaces ?
    }
    // the word 'end' hasn't been found, so return an empty string
    return "";
}

Upvotes: 1

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