CODEWITHSUNDEEP
sqldatediff
JBrewer
JBrewer

Reputation: 13

Calculate full years and partial months between 2 dates

I'd like to know how to calculate full years and number of full months between two dates and combine them into one column:

Ex: My beginning date is a column named "TransferDate" = 7/1/2017 and Today (11/14/2019) My desired output would be a column named "Age" = 2.3

2 Full Years (2017 - 2019) .3 Full Months (August, September & October)

Upvotes: 1

Views: 523

Answers (2)

Matthew Eskolin
Matthew Eskolin

Reputation: 658

This combines the year and month components into a single column after calculating them as monthdif and yeardif.

DECLARE @start DATETIME = '07/01/2017'
DECLARE @end DATETIME = '11/14/2019'

select CAST((CAST(x.yeardif as nvarchar(20)) + '.' + CAST(x.monthdif as nvarchar(20))) as decimal(5,2)) from
(select DATEDIFF(yyyy,@start,@end) yeardif,DATEDIFF(m,@start,@end) - (12 * DATEDIFF(yyyy,@start,@end)) - 1 monthdif) x

Upvotes: 0

bd_iii
bd_iii

Reputation: 163

Take a look and see if this gives you what you are looking for.

Declare @date1 date = '11/01/2001'
Declare @date2 date = '12/01/2002'

Select @date1
    ,@date2
    ,Case 
    when datediff(M,@date1,@date2) < 12 then ''
    when datediff(M,@date1,@date2) < 24  then 'one year'
    else cast(floor(datediff(M,@date1,@date2)/12) as varchar(20)) + ' Years'
    end  +  ' ' +
Case 
    when datediff(M,@date1,@date2) - floor(datediff(M,@date1,@date2)/12)*12 = 0  then ''
    when datediff(M,@date1,@date2) - floor(datediff(M,@date1,@date2)/12)*12 = 1 then 'one month'
    else cast(datediff(M,@date1,@date2) - floor(datediff(M,@date1,@date2)/12)*12 as varchar(20)) + ' Months'
    end

Upvotes: 1

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