CODEWITHSUNDEEP
c#jsonsystem.text.json
SandroRiz
SandroRiz

Reputation: 1097

System.Text.JSON doesn't deserialize what Newtonsoft does

I have a json that the new System.Text.Json.JsonSerializer.Deserialize<T>(json_data) serialize as List<T> with the correct numbers of elements, but then the objects inside have all the values null or 0

Same json with Newtonsoft.Json.JsonConvert.DeserializeObject<T>(json_data) is correctly filled.

Class:

public class SensorValue
    {
        public string StationCode { get; set; }
        public string SensorCode { get; set; }
        public string SensorNameIt { get; set; }
        public string SensorNameDe { get; set; }
        public string SensorNameLd { get; set; }
        public string SensorUnitMeasure { get; set; }
        public DateTime SamplingDateTime { get; set; }
        public Decimal SamplingValue { get; set; }
    }

JSON

[{"stationCode":"89190MS","sensorCode":"LT","sensorNameIt":"Temperatura dell´aria","sensorNameDe":"Lufttemperatur","sensorNameLd":"Temperatura dl’aria","sensorUnitMeasure":"°C","samplingDateTime":"2019-11-15T15:10:00","samplingValue":0.3},{"stationCode":"89190MS","sensorCode":"N","sensorNameIt":"Precipitazioni","sensorNameDe":"Niederschlag","sensorNameLd":"plueia","sensorUnitMeasure":"mm","samplingDateTime":"2019-11-15T15:10:00","samplingValue":0.4},{"stationCode":"89190MS","sensorCode":"WR","sensorNameIt":"Direzione del vento","sensorNameDe":"Windrichtung","sensorNameLd":"Direzion dl vënt","sensorUnitMeasure":"° ","samplingDateTime":"2019-11-15T15:10:00","samplingValue":165.7},{"stationCode":"89190MS","sensorCode":"WG","sensorNameIt":"Velocità del vento","sensorNameDe":"Windgeschwindigkeit","sensorNameLd":"Slune dl vënt","sensorUnitMeasure":"m/s","samplingDateTime":"2019-11-15T15:10:00","samplingValue":0.7},{"stationCode":"89190MS","sensorCode":"WG.BOE","sensorNameIt":"Velocitá raffica","sensorNameDe":"Windgeschwindigkeit Böe","sensorNameLd":"Slune dl vënt","sensorUnitMeasure":"m/s","samplingDateTime":"2019-11-15T15:10:00","samplingValue":1.3},{"stationCode":"89190MS","sensorCode":"LF","sensorNameIt":"Umidità relativa","sensorNameDe":"relative Luftfeuchte","sensorNameLd":"Tume relatif","sensorUnitMeasure":"%","samplingDateTime":"2019-11-15T15:10:00","samplingValue":100.0},{"stationCode":"89190MS","sensorCode":"LD.RED","sensorNameIt":"Pressione atmosferica","sensorNameDe":"Luftdruck","sensorNameLd":"Druch dl’aria","sensorUnitMeasure":"hPa","samplingDateTime":"2019-11-15T15:10:00","samplingValue":1006.9},{"stationCode":"89190MS","sensorCode":"GS","sensorNameIt":"Radiazione globale ","sensorNameDe":"Globalstrahlung","sensorNameLd":"Nraiazion globala ","sensorUnitMeasure":"W/m²","samplingDateTime":"2019-11-15T15:10:00","samplingValue":3.8},{"stationCode":"89190MS","sensorCode":"SD","sensorNameIt":"Durata soleggiamento","sensorNameDe":"Sonnenscheindauer","sensorNameLd":"Dureda dl surëdl","sensorUnitMeasure":"s","samplingDateTime":"2019-11-15T15:10:00","samplingValue":0.0}]

Any help ? consoleapp project .net core 3.0.0 newtonsoft 12.0.3

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Upvotes: 29

Views: 28296

Answers (5)

Ali Karaca
Ali Karaca

Reputation: 3851

For setting globally, in Program.cs / Startup.cs set

services.AddControllers(options =>
{
    //...
}).AddJsonOptions(options =>
{
    options.JsonSerializerOptions.PropertyNameCaseInsensitive = true;
    options.JsonSerializerOptions.Encoder = JavaScriptEncoder.Default;
});

Upvotes: 12

PhiseySt
PhiseySt

Reputation: 158

I had a problem getting default values instead of real ones. When I forgot to add an identifier to the properties of the model in the current project (set). Prior to using serialization/deserialization, only the identifier (get) was required for properties in the model. But for me both libraries (System.Text.Json and NewtonSoft )returned the default value. This is not the case of the topic starter.

Upvotes: 5

John
John

Reputation: 1247

You can also apply JsonPropertyName attributes to the model properties.

[JsonPropertyName("yourSourceJsonKey")]
public string YourPropertyName { get; set; }

https://learn.microsoft.com/en-us/dotnet/standard/serialization/system-text-json-customize-properties#customize-individual-property-names

This article describes the behaviour of the serialiser:

https://learn.microsoft.com/en-us/dotnet/standard/serialization/system-text-json-how-to?pivots=dotnet-core-3-1#serialization-behavior

Upvotes: 1

Felipe Augusto
Felipe Augusto

Reputation: 1553

if (response.IsSuccessStatusCode)
{
   var json = await response.Content.ReadAsStringAsync();

   var options = new JsonSerializerOptions
   {
       WriteIndented = true,
       PropertyNameCaseInsensitive = true // this is the point
   };

   var books = JsonSerializer.Deserialize<IEnumerable<Book>>(json, options);
}

Upvotes: 1

Klaycon
Klaycon

Reputation: 11080

The default behavior of the System.Text.Json deserializer is to match properties as case sensitive. You need to pass options telling it to match case insensitive:

using System.Text.Json;

JsonSerializer.Deserialize<T>(json_data, new JsonSerializerOptions 
{
    PropertyNameCaseInsensitive = true
});

Upvotes: 91

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