CODEWITHSUNDEEP
javaarrays
Xalvetra
Xalvetra

Reputation: 17

Index 0 out of bounds for length 0 Array 3D

I am using a 3D array int the below code i am getting array index out of bound error below is the code for the same:-

package array2d;

import java.util.Scanner;

public class Array3 {

    public static void main(String[] Args) {
        Scanner vee= new Scanner(System.in);
        int penilaian[][][];
        int mahasiswa[];

        for (int i = 0; i < 5; i++) {
            System.out.print("Class" + (i + 1) + " : ");
            int mhs = vee.nextInt();

            System.out.println("------------------------------------------------");
            mahasiswa = new int[mhs];

            penilaian = new int[i][mahasiswa.length][3];

            for (int j = 0; j < mahasiswa.length; j++) {
                System.out.print("Score Mid Test" + (i + 1) + " Ke -" + (j + 1) + " :");
                penilaian[i][j][0] = vee.nextInt();
                System.out.print("Score Test" + (i + 1) + " Ke -" + (j + 1) + " :");
                penilaian[i][j][1] = vee.nextInt();
                System.out.print("Score Project" + (i + 1) + " Ke -" + (j + 1) + " :");
                penilaian[i][j][2] = vee.nextInt();
                System.out.println("=======================================================================");

            }
        }
    }

}

Getting the below error:-

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Index 0 out of bounds for length 0 at array2d.TugasArray3.main(TugasArray3.java:27) Score Mid Test1 Ke -1

Upvotes: 0

Views: 2472

Answers (1)

mitra
mitra

Reputation: 16

you declare a three-dimensional (3d) array penilaian = new int[i][mahasiswa.length][3]; when i=0 the size of first element is 0 therfore you cant assign any value to this array

Upvotes: 0

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