Reputation: 15692
I have a Rust struct like this:
pub struct SomeMapping {
pub id: String,
pub other_id: Option<String>,
pub yet_another_id: Option<String>,
pub very_different_id: Option<String>
}
What is the simplest way to check if all optional ids are not set? I know the syntax like
if let Some(x) = option_value {...}
to extract a value from an Option
, but I don't get how to use this in a concise way to check multiple values for None
.
Upvotes: 5
Views: 3257
Reputation: 13942
You can destructure a structure in pattern matching like so:
pub struct SomeMapping {
pub id: String,
pub other_id: Option<String>,
pub yet_another_id: Option<String>,
pub very_different_id: Option<String>,
}
fn main() {
let x = SomeMapping {
id: "R".to_string(),
other_id: Some("u".to_string()),
yet_another_id: Some("s".to_string()),
very_different_id: Some("t".to_string()),
};
if let SomeMapping {
id: a,
other_id: Some(b),
yet_another_id: Some(c),
very_different_id: Some(d),
} = x {
println!("{} {} {} {}", a, b, c, d);
}
}
It is documented in the Rust book chapter 18.
Upvotes: 8